Answer:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Step-by-step explanation:
Hello!
We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.
We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:
- The radial coordinate which is often denoted by r.
- The angular coordinate by θ.
So we need to find r and θ. So we know that:
(1)
x = rcos(θ) (2)
x = rsin(θ) (3)
From the statement we know that (x, y) = (3, -3).
Using the equation (1) we find that:
Using the equations (2) and (3) we find that:
3 = rcos(θ)
-3 = rsin(θ)
Solving the system of equations:
θ= -45
Then:
r = 3\sqrt{2}[/tex]
θ= -45 or 315
Notice that there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.
So, the solution is:
(3 square root of 2 , 135°), (-3 square root of 2 , 315°)
Answer:
The 1st answer that is (0,7) will be No
The 2nd answer that is (3,21) will be Yes
The 3rd answer that is (8,56) will bw Yes
Label your sides= hypotenuse(h),opposite(o),adjacent(a)
hypotenuse=longest(opposite the right angle)
opposite= opposite the other angle
adjacent= the other side
see which sides are involved
in this case it is adjacent and hypotenuse
so A and H
we have to use the SOHCAHTOA rule
Sin=o/h Cos=a/h Tan=o/a
we use cos because a and h are involved
Cos(15°)=62/x
rearrange the equation to find x
x= 62/cos(15)
put this in your calculator
x= 64.12
Most textbooks interpret standard form of a quadratic function to be as follows:
f(x) =
In the function f(x) =
, notice we do not have a value for "c". Just place a "0" in for the c and you have standard form.
the criteria for standard form:
1. All like terms are combined
2. Degree must drop from left to right
3. The leading coefficient cannot be equal to zero.
Answer:
true
Step-by-step explanation:
