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Alja [10]
2 years ago
11

Which equation has 1 solution? IwI = -2 IwI = -1 IwI = 0 IwI = - 1

Mathematics
1 answer:
vovangra [49]2 years ago
6 0
Absolute value is alwas positive
so all of them excet the 3rd one are false

|w|=0 has 1 solution


if the last one was |w|=1 then ther would be 2 solutions, -1 and 1


answer is |w|=0
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If x is divided by 5 the remainder is 4. If why is divided by 5 the remainder is 1. What is the remainder when x+y is divided by
Naddik [55]

Answer:

0

Step-by-step explanation:

We are given the following:

\frac{x}{5}=q_1+\frac{4}{5}      (equ. 1)

\frac{y}{5}=q_2+\frac{1}{5}      (equ. 2)

We are asked:

\frac{x+y}{5}=q_3+\frac{r}{5}  (equ. 3) , what is r?

The q_i's represent the quotients you get.

r is the remainder of dividing x+y by 5.

We know that r is a number in {0,1,2,3,4}.

x=5q_1+4 (I got this by multiplying both sides of equ 1. by 5.)

y=5q_2+1 (I got this by multiplying both sides of equ 2. by 5.)

Let's add these equations together:

x+y=(5q_1+5q_2)+(4+1)

Factoring the 5 out for the q_i's part and simplify 4+1 gives:

x+y=5(q_1+q_2)+5

So 5 can't be the remainder of dividing something by 5 but see that we can factor this right hand expression more as:

x+y=5(q_1+q_2+1)

So q_3=q_1+q_2+1 while there is no remainder (the remainder is 0).

Let's do an example if you are not convinced at this point that the remainder will be 0.

So choose x=9 since 9/5 gives a remainder of 4.

And choose y=16 since 16/5 gives a remainder of 1.

x+y=9+16=25 and 25/5 gives a remainder of 0.

8 0
2 years ago
Plz help me I’ll give brainliest
luda_lava [24]

Answer:

it is A i could be wrong

Step-by-step explanation:

4 0
3 years ago
2x + 4y = 14<br> 3x - 4y = -39
cestrela7 [59]

Answer:

2x + 4y = 14 = x= −2y+7

3x - 4y = -39= x=  4=3 y−13

Step-by-step explanation:

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3 years ago
Can the polynomial equation have exactly 1 real solution, including any repeated solutions? (Use the Fundamental Theorem of Alge
Kryger [21]

yes, there are infinitety many polynomial that have exactly one real root just like your example, to determine the real root first let the real root is a, and the complex roots are b±ic the polynomial satisfy

-9x³ + 19x² + 17 = -(x - a)(x - b - ic)(x - b + ic)

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5 0
3 years ago
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KonstantinChe [14]

Answer:

2n-4

Step-by-step explanation:

it isn't actually lololololol reeeeèeee. Nah jk it is

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