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3 years ago

Write in standard form an equation for the line with slope 1/3 through the point (2,-2).

Mathematics

1 answer:

Alexxandr [17]3 years ago

6 0

Answer:

x - 3y = 8.

Step-by-step explanation:

Use the point-slope form of the equation of a line:

y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.

So substituting the given values:

y - (-2) = 1/3(x - 2)

y + 2 = 1/3x - 2/3 Multiply through by 3:

3y + 6 = x - 2

x - 3y = 6 + 2

x - 3y = 8 <---- Standard Form.

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3 years ago

Ms. Higgins would like for her homework assignments to have three addition problems for every five subtraction problems. If she

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3 years ago

Look at this cylinder:

Sedbober [7]

Height=h=8cm
Radius=r=4cm

We know

$\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2$

Now

New Radius=2(4)=8cm
New Height=2(8)=16cm

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}$

Hence our correct option is Option C

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2 years ago

PLZ HURRY <br> which expression is equivalent to (5r + 2) +- (4x - 3)?

Sever21 [200]

Step-by-step explanation:

Answer : 5r−4x+5

hope I helped c:

Insta: brianna_editsz

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3 years ago

A motorcycle can travel 48 miles for every gallon of gas used

trasher [3.6K]

Answer:

48 miles multiplied by x amount of gallons

Step-by-step explanation:

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3 years ago

Read 2 more answers