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3 years ago

ABCD is an irregular quadrilateral. The sum of all the interior angles is 360 degrees. What is the measure of angle D?

Mathematics

1 answer:

pav-90 [236]3 years ago

8 0

Answer:

D. Need more information

Step-by-step explanation:

The given information is not sufficient to determine each angle measure since the quadrilateral is irregular.

It would be good to see the picture at least.

Possible options are A or B but we can't confirm without additional detals, option C can't be a correct choice as 180° represents a straight line.

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Can someone help me with this problem? Its due today plz i need help! I will give brainlist if it is right!

d1i1m1o1n [39]

Answer:

A (-4,0), B (0,3) and C (-6,5)

Step-by-step explanation:

The coordinates for A are (-4,-3) B (0,0) and C (-6,2)

From there just add 3 to all theY values

The coordinates of the translated triangle would be A (-4,0), B (0,3) and C (-6,5)

Hope that helps!

7 0

3 years ago

Write the fact family for the numbers 32,8,and 4

katovenus [111]

Assuming that you meant factor family to be a factor tree.

32 8 4
16 2 4 2 2 2
4 4 2 2
2 2 2 2

3 0

4 years ago

Fill in the other coordinate for the line y=23x+3 y = 2 3 x + 3 : (3, )

Igoryamba

23(3) + 3

= 72

Why do you write 2 equations?

5 0

4 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

mr_godi [17]

Answer:

correct option for first blank is 5/4 and for second blank is $\frac{ 3i\sqrt{7}}{4}$

i.e m= $\frac{5}{4}\pm\frac{ 3i\sqrt{7}}{4}$

Step-by-step explanation:

The given equation

$m^2 - \frac {5m}{2} = \frac{-11}{2}$

and we have to find m= ______ ± ________

We can use quadratic formula to solve this question.

The above equation can be written as: $m^2 - \frac {5m}{2} + \frac{11}{2} = 0$

and the formula used will be:

$m= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values of a= 1, b= -5/2 and c= 11/2 and solving we get: $m=\frac{-\frac{-5}{2}\pm\sqrt{{(\frac{-5}{2})}^2-4(1)(\frac{11}{2})}}{2(1)}\\\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{25}{4})-22}}{2}\\m=\frac{\frac{5}{2}\pm\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{\frac{5}{2}}{2}\pm\frac{\sqrt{(\frac{-63}{4})}}{2}\\m= \frac{5}{4}\pm\frac{\sqrt{-63}}{4}$

Since there is - sign inside the √ so $\sqrt{-1}$ is equal to i and we have to divide $\sqrt{63}$ into its multiples such that the square root of one multiple is whole no so,