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snow_tiger [21]
3 years ago
8

Please help and show work i need it asap

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
6 0
Answer:
X=9

Please see the picture attached!

I hope this helps :) comment if you have any questions!

IgorC [24]3 years ago
6 0
9???????!????????????????!?!!!!
You might be interested in
2. Which of the following numbers is not greater than -7.4
Zinaida [17]

Answer:

a. -8.1

The numbers that are greater than -5 are -2, 3 and 0.

Hope it helps.

6 0
3 years ago
Which of the following expressions is equivalent to?
gayaneshka [121]

Answer:  

It's the last choice:  2x^2 - 5x - 8 - 37/(x - 5).

Step-by-step explanation:

Long division:

        2x^2 - 5x -8    <---------------Quotient

        ---------------------------------

x - 5 ) 2x^3 - 15x^2 + 17x + 3

          2x^3 - 10x^2

                     - 5x^2 + 17x

                     - 5x^2  + 25x

                                   - 8x + 3

                                   - 8x + 40

                                           -37 <------ Remainder.

7 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPP
OverLord2011 [107]

Answer:

11

Step-by-step explanation:

1st plug in the given numbers for each variable (the letters)

4 x 6 ÷ 3 + 3 =

Next, use the order of operations to solve the expression.

4 x 6 ÷ 3 + 3 =

24 ÷ 3 + 3 =

8 + 3 = 11

7 0
3 years ago
Read 2 more answers
A. Determine the value of an account in which a person invested $6000 for 12 years at an annual rate of 9% compounded annually (
Sliva [168]

Answer:

16875.98

Step-by-step explanation:

6000(1+(0.09/1)^1*12 = 16875.98

8 0
3 years ago
Read 2 more answers
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