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2 years ago

Please help and show work i need it asap

Mathematics

2 answers:

Veseljchak [2.6K]2 years ago

6 0

Answer:
X=9

Please see the picture attached!

I hope this helps :) comment if you have any questions!

IgorC [24]2 years ago

6 0

9???????!????????????????!?!!!!

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A rectangle has an area of (12m-30n) square units. Its width is 6 units. Factor the expression for the area to find an expressio

garik1379 [7]

Answer: 2m - 5n

<u>Explanation:</u>

Using long division

6 ) 12m - 30n

width*length = area

6(2m - 5n) = 12m - 30n

5 0

3 years ago

Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a

pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

$ax^2 + bx + c =0$

Where, [ a , b and c are constants ]

- The quadratic formula is given as:

$x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}$

- The given equation is:

$x^2 + 2x - 120 = 0$

Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

$x = \frac{-2+/-\sqrt{2^2 - 4*1*(-120)} }{2*1}\\\\x = \frac{-2+/-\sqrt{4 + 480} }{2}\\\\x = \frac{-2+/-(22) }{2}\\\\\\x = 10 , -12$

7 0

3 years ago

PLEASE HELP 25 POINTS!!!

miss Akunina [59]

Sequence: 2 + 1 + 1/2 + 1/4 + 1/8 + ...

Explanation:

Here Given Sum to Infinity

$\sf S \infty \ =a_1 \ x \ \dfrac{1}{1-r}$

Identify following

a1 = 2

r = 1/2

Solve:

$\rightarrow \sf S \infty \ =2 \ x \ \dfrac{1}{1-\frac{1}{2} }$

$\rightarrow \sf S \infty \ =4$

The sum of this infinity series is 4

5 0

1 year ago

The track pine middle school is 1/3 of a mile for each lap. mathew walked around the track and completed 9 laps in one hour. how

Nina [5.8K]

He walked 3 miles in an hour. He would have to also walk 9 laps in 45 minutes to walk the same amount. Not sure what your question is?

7 0

3 years ago

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

ipn [44]

Answer:

$x = 1 + \sqrt5, x = 1 - \sqrt5$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: $ax^2 + bx + c = 0$

Quadratic Formula: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $g(x) = x^2 - 2x - 4$

a = 1
b = -2
c = -4

Plug the values into the equation and solve.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}$
$x = \frac{2\pm\sqrt{4 +16}}{2}$
$x = \frac{2\pm\sqrt{20}}{2}$
$x = \frac{2\pm\sqrt{4 * 5}}{2}$
$x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}$
$x = \frac{2\pm2\sqrt5}{2}$
$x = 1 + \sqrt5, x = 1 - \sqrt5$

7 0

2 years ago