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algol13
4 years ago
14

The weight of an object is the force generated by Earth's gravity accelerating the object's ______.

Mathematics
2 answers:
stepan [7]4 years ago
7 0

Answer: Speed

Step-by-step explanation:

Andrej [43]4 years ago
5 0

Answer:

mass

Step-by-step explanation:

From the universal law of gravity

F=G\frac{Mm}{r^2}

Where

G = Gravitational constant = 6.674×10⁻¹¹ m³/kg⋅s²

M = Mass of Earth = 5.972×10²⁴ kg

r = Radius of Earth = 6.371×10⁶ m

\\\Rightarrow ma=G\frac{Mm}{r^2}\\\Rightarrow a=G\frac{M}{r^2}\\\Rightarrow a=6.674\times 10^{-11}\frac{5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81\ m/s^2

So the force of gravity acting on the mass of an object is

W = m×9.81

∴ Weight of an object is the product of <u>mass</u> and acceleration due to gravity

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Samuel is saving to buy a watch that costs $169.This is $48 More than 4 times what he saved last month.How much did he save last
bazaltina [42]
He saved 30.25 last month. 169 - 48 = 121 divided by 4 = 30.25
8 0
3 years ago
Read 2 more answers
Part A: Solve –mk – 120 &gt; 95 for m. Show your work.
Jlenok [28]
-mk - 120 > 95
-mk > 95 + 120
-mk > 215
m < -215/k
=============
2c - 9f = 45
-9f = -2c + 45
f = 2/9c - 5...or it could be (-2c + 45) / -9
7 0
4 years ago
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By rounding to 1 significant figure, estimate<br> 542.04 x 1.88=
Verizon [17]

Answer:

542.04 × 1.88 = 1020

Facts about 1,020

Sig Figs

3

1020

Decimals

0

Scientific Notation

1.02 × 103

E-Notation

1.02e+3

Words

one thousand twenty

4 0
3 years ago
Simplify 16x² - 9y²/(4x-3y)^2​
const2013 [10]

9514 1404 393

Answer:

  (4x +3y)/(4x -3y)

Step-by-step explanation:

  \dfrac{16x^2-9y^2}{(4x -3y)^2}=\dfrac{(4x)^2-(3y)^2}{(4x-3y)^2}=\dfrac{(4x-3y)(4x+3y)}{(4x-3y)(4x-3y)}\\\\=\boxed{\dfrac{4x+3y}{4x-3y}}

4 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
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