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pshichka [43]
3 years ago
9

From 1986-1996, drug overdose deaths per 100,000 began to rise. Numbers for each year are 2,1,2,2,1,2,2,3,3,3,3. What is the mea

n of these statistics?
Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
To find the mean you need to all of the numbers together and then divide by how many numbers it is . the answer is 2.1
strojnjashka [21]3 years ago
5 0
To find the mean, add all the numbers together and then divide it by how many numbers there are:
2+1+2+2+1+2+2+3+3+3+3=24
There are eleven numbers total, so divide 24 by 11.
24/11=2.1818181818181818.....
The mean of the statistics is approximately 2.2
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mixas84 [53]
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7 0
3 years ago
The area of a rectangle is 48. If the width is 8 less than its
Rufina [12.5K]

OK.... here we go....

The width is 8 less than the length, so that means: w = L - 8.

So, since the area of a rectangle is: A = L x W ...

Therefore, 48 = L(L - 8)...

48 = L^2 - 8L...

continuing from there .... you get width = 4 and length = 12

48 = 4 x 12   (and notice that the width is 8 less than the length)



7 0
4 years ago
According to Reuters, a survey undertaken by the National Center for Health Statistics revealed that about 25% of U.S. household
ddd [48]

Answer:

a) P=0.8

b) P=0.67

c) P=0.05

d) P=0.33

e) P=0.45

Step-by-step explanation:

a. What is the probability that the household has only a cell phone and has high-speed Internet?

This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.

P(C\&I)=0.8

b. What is the probability that the household has only a cell phone or has high-speed Internet?

This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).

P(C\,orI\,)=P(C)+P(I)-P(C)*P(I|C)=0.25+0.65-(0.25*0.8)=0.25+0.62-0.20=0.67

c. What is the probability that the household has only a cell phone and does not have high-speed Internet?

This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.

P(C\&\bar I)=P(\bar I|C)*P(C)=(1-P(\I|C))*P(C)=(1-0.8)*0.25 = 0.2*0.25 = 0.05

d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?

This probability is complementary of the one calculated in Point (c).

P(\bar C \,or\, \bar I)=1-P(C\, or\,I)=1-0.67=0.33

e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?

This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).

P(\bar C\&I)=P(I)-P(I|C)*P(C)=0.65-0.8*0.2=0.65-0.2=0.45

7 0
3 years ago
PLEASE HELP PLEASEEEEEEEEEEEEEEEEEEEEEEEE <br> PLEASE ANSWER :( i LL GIVE BRAINLIEST
Dafna11 [192]

Answer:

the second one goes in first the 1 one goes in last the 3 one goes in on the 3 one a the last one goes on the second one


Step-by-step explanation:


3 0
4 years ago
What is the gcf of 10 and 25
HACTEHA [7]
The gcf of 10 and 25 is 5
5 0
3 years ago
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