The correct answer is: AB
Explanation:
There are two ways you can understand this:
1. By drawing:
A ------ C ------B
As you can see the point C is between A and point B, hence AC + CB = AB. One thing to remember here is that point C can be anywhere between the point A and B, in that case, the answer will remain be the same AB. For instance:
A --- C -------------B
Again, AC + CB = AB.
2. By inference:
If the point C is between points A and B, it means that the point C lies on the line AB; if point C were not on the line AB, it will not be between points A and B. Hence, you can infer that AB is a line and point C lies on it and is between points A and B.
Answer:
8 hours
Step-by-step explanation:
Let's first find how many inches the candle would have burned in 1 hour.
6 in:12 hours
x: 1 hour
We can divide 12 by 12 to get 1. This means we need to divide 6 by 12 to get x
x=1/2 inches
1/2 inches:1 hour
4 inches: x hours
We divide 4 by 1/2 to get 8. 1/2*8=4. This means...
x=1 hour*8=8 hours
Answer:
slope 1.5, passes through (0, 5) 62/87,21 Substitute m = 1.5 and ( x, y) = (0, 5) in the equation y
Step-by-step explanation:
boom
Answer: (0.63, 7.07)
Step-by-step explanation:
The confidence interval for population proportion is given by :-

Given :
; 
Significance level : 
Critical value : 
Now, a 90% confidence interval for population proportion will be :-

Hence, a 90% confidence interval for population proportion = (0.63, 7.07)
Answer:
The correct answer is second quadrant.
Step-by-step explanation:
Vertices of J ≡ (3 , -5) which shows J is in fourth quadrant. When J is reflected across the line y = -1, the point J moves to first quadrant as J' with coordinates (3 , 3).
Vertices of K ≡ (-8 , -1) which shows K is in third quadrant. When K is reflected across the line y = -1, the point K remains where it is (in the third quadrant) as it is on the line y = -1 only.
Vertices of L ≡ (5 , 1) which shows L is in first quadrant. When L is reflected across the line y = -1, the point L moves to fourth quadrant as L' with coordinates (5 , -3).
Thus each of the first, fourth and third quadrant contains a vertex except the second quadrant.