This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>
SA=201.7cm^2
I used the equation
SA=pi^1/3(6*V)^2/3 in case you have any more questions like this
Answer:
Step-by-step explanation:
To eliminate the x terms, first multiply the second equation by 3:
-3x + 6y = 24
then add it to the first equation:
3x + 5y = -2
-3x + 6y = 24
------------------
0x + 11y = 22
y = 2
plug the value of y into one of the equations:
-x + 2(2) = 8
x = 4-8 = -4
(x,y) = (-4, 2)
The answer is C
Explanation:
2x-14=4
+14 +14
2x= 18
/2 /2
x= 9
Answer:Its A
Step-by-step explanation:-17+12=-5 I hope ive helped u Have an wonderful day or night!