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Aleonysh [2.5K]

3 years ago

15

Racquetballs are sealed in a pressurized container to maintain the rebound percentage

1 answer:

masha68 [24]3 years ago

3 0

Answer:

1.182 meters.

Step-by-step explanation:

We have that the initial height is 3 meters, we know that after each rebound it recovers 83% of the original height, therefore:

First bounce:

3 * 0.83 = 2.49

Second bounce:

2.49 * 0.83 = 2.0667

We can deduce a formula here:

hn = 3 * (0.83) ^ n

where is the bounce number, we know that the bounce number that we want to find the height is 5, therefore:

h5 = 3 * (0.83) ^ 5

h5 = 1.182

which means that at the fifth bounce, the height is 1.182 meters.

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Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 280 days a

a_sh-v [17]

First, find the z-score:

z = (value - mean) / sdev
= (275 - 280) / 15
= - 0.33

In order to use a standard normal table, we need a positive z-score:
P(z < -0.33) = 1 - P(z < 0.33)

Looking at the table, we find P(z < 0.33) = 0.6293

Therefore:
P(z < -0.33) = 1 - 0.6293 = 0.3707

Hence, you have a probability of about 37% <span>that a randomly selected pregnancy lasts less than 275 days.</span>

4 0

3 years ago

What is the inverse of this function?

kolbaska11 [484]

Answer:

$f^{-1}(x)=4x^2-3$

Step-by-step explanation:

<u>The Inverse of a Function</u>

Given a function f(x), the inverse of f, called $f^{-1}(x)$ is a function that satisfies:

$f(f^{-1}(x))=x$

The domain of f becomes the range of its inverse and vice-versa.

The procedure to find the inverse of the function is:

* Write the function as a two-variable equation:

* Solve the equation for x.

* Swap the variables

We are given the function:

$\displaystyle f(x)=-\frac{1}{2}\sqrt{x+3}$

Defined in the interval x ≥ -3

Note f is always negative, thus its range is f(x) ≤ 0

Now we find the inverse. Call y=f(x):

$\displaystyle y=-\frac{1}{2}\sqrt{x+3}$

Multiplying by 2:

$\displaystyle 2y=-\sqrt{x+3}$

Squaring both sides:

$\displaystyle 4y^2=x+3$

Subtracting 3:

$\displaystyle 4y^2-3=x$

Swapping variables:

$y=4x^2-3$

Thus:

$\mathbf{f^{-1}(x)=4x^2-3}$

The domain of the inverse is the range of f, thus x is restricted to

x ≤ 0

5 0

3 years ago

Can someone please please help me

Rufina [12.5K]

Answer:

Vertical

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Algebra 1 B Unit 7 Lesson 2 Semester B Someone please Help

Dafna1 [17]

What would you like help with?

6 0

3 years ago

Points B, D, and F are midpoints of the sides of ACE. EC = 32 and BF = 2x - 10. Find the value of x.

Svetlanka [38]

Answer:

13

Step-by-step explanation:

Remark

This only works if B is between AC and F is between AE

Givens

CE = 32

BF = 1/2 CE Properties of midpoints. BF is parallel to and 1/2 of CE

BF = 1/2 * 32

BF = 16

Equation

2x - 10 = 16 Add 10 to both sides

2x - 10 + 10 = 16 + 10 Combine

2x = 26 Divide by 2

2x/2 = 26/2 Do the division

x = 13

4 0

4 years ago