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4 years ago

6

You are setting up a PCR reaction and add a primer for one end of the target sequence, but you forget to add the primer for the

other end of the target sequence. If you added the other necessary components, what do you expect to observe after running the PCR reaction for 40 cycles

1 answer:

Arlecino [84]4 years ago

6 0

Answer:

It will carry out PCR.

Step-by-step explanation:

If only one primer is added, it can still form a product, which is used in the sequencing reactions. The product formed will be only single stranded because of the presence of single primer.

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What is the radius of a circle whose area is 36π cm^2<br><br> (to the second power)

Pavel [41]

I think 3.39 im not sure

7 0

4 years ago

A leaking pond loses 20 gallons of water in 49 hours. How many gallons of water will it lose in 5 hours? Round to one decimal pl

White raven [17]

Answer:

12.25

Explanation

49/20 <em><u>(which is the same as (</u></em><em><u>4</u></em><em><u>9</u></em><em><u>÷</u></em><em><u>2</u></em><em><u>0</u></em><em><u>))</u></em><em><u> </u></em>=2.45

<em><u>Multiply</u></em><em><u> </u></em><em><u>2</u></em><em><u>.</u></em><em><u>4</u></em><em><u>5</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>hours</u></em><em><u> </u></em><em><u>(</u></em><em><u>5</u></em><em><u>)</u></em><em><u> </u></em>

$2.45 \times 5 = 12.25$

=12.25

5 0

3 years ago

Read 2 more answers

Please help me out with this please

ki77a [65]

Answer:

P = 9 is the max value

Step-by-step explanation:

Sketch

2x + 4y = 10

with x- intercept = (5, 0) and y- intercept (0, 2.5)

x + 9y = 12

with x- intercept = (12, 0) and y- intercept = (0, $\frac{4}{3}$ )

Solve

2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)

The region corresponding to the solution of the system of constraints

Has vertices at (0, $\frac{4}{3}$ ), (0, 0) , (5, 0) and (3, 1)

Now evaluate the objective function at each vertex.

(0, 0) can be excluded as it will not give a maximum

(5, 0) → P = 5 + 0 = 5

(0, $\frac{4}{3}$ ) → 0 + 8 = 8

(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value

Thus the maximum value is 9 when x = 3 and y = 1

7 0

3 years ago

What is the definition of math

nata0808 [166]

Answer:

a subject in school in which you learn to do things with numbers

3 0

3 years ago

Read 2 more answers

A small plane took 3 hours to fly 960 km from Ottawa to Halifax with a tail wind. On the return trip, flying into the wind, the

Rina8888 [55]

Answer:

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

Step-by-step explanation:

This problem involves two unknowns:

wind speed, and
speed of the plane in still air.

Let the speed of the wind be $x \rm \; km \cdot h^{-1}$ , and the speed of the plane in still air be $y\rm \; km \cdot h^{-1}$ . It takes at least two equations to find the exact solutions to a system of two variables.

Information in this question gives two equations:

It takes the plane three hours to travel $\rm 960\; km$ from Ottawa to with a tail wind (that is: at a ground speed of $x + y$ .)
It takes the plane four hours to travel $\rm 960\; km$ from Halifax back to Ottawa while flying into the wind (that is: at a ground speed of $-x + y$ .)

Create a two-by-two system out of these two equations:

$\left\{ \begin{aligned}&3(x + y) = 960 && (1) \\ &4(-x + y) = 960 && (2) \end{aligned}\right.$ .

There can be many ways to solve this system. The approach below avoids multiplying large numbers as much as possible.

Note that this system is equivalent to

$\left\{ \begin{aligned}&4 \times 3 (x + y) = 4\times960 && 4 \times (1) \\ &3\times 4(-x + y) = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

$\left\{ \begin{aligned}&12 x + 12y = 4\times960 && 4 \times (1) \\ &- 12x + 12y = 3\times 960 && 3 \times (2) \end{aligned}\right.$ .

Either adding or subtracting the two equations will eliminate one of the variables. However, subtracting them gives only $1 \times 960$ on the right-hand side. In comparison, adding them will give $7 \times 960$ , which is much more complex to evaluate. Subtracting the second equation ( $3 \times (2)$ ) from the first ( $4 \times (1)$ ) will give the equation

$(12 - (-12) x = 1 \times 960$ .

$24 x = 960$ .

$x = 40$ .

Substitute $x$ back into either equation $(1)$ or $(2)$ of the original system. Solve for $y$ to obtain $y = 320$ .

In other words,

Wind speed: $\rm 40\; km \cdot h^{-1}$ .
Speed of the plane in still air: $\rm 320\; km \cdot h^{-1}$ .

3 0

3 years ago

Read 2 more answers