Answer:
32.66 units
Step-by-step explanation:
We are given that

Point A=(-2,-4) and point B=(1,20)
Differentiate w.r. t x

We know that length of curve

We have a=-2 and b=1
Using the formula
Length of curve=
Using substitution method
Substitute t=12x+14
Differentiate w.r t. x


Length of curve=
We know that

By using the formula
Length of curve=![s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7Bt%7D%7B2%7D%5Csqrt%7B1%2Bt%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%28t%2B%5Csqrt%7B1%2Bt%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=![s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B1%7D%7B12%7D%5B%5Cfrac%7B12x%2B14%7D%7B2%7D%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%2B%5Cfrac%7B1%7D%7B2%7Dln%2812x%2B14%2B%5Csqrt%7B1%2B%2812x%2B14%29%5E2%7D%29%5D%5E%7B1%7D_%7B-2%7D)
Length of curve=
Length of curve=
Length of curve=
10% = 15.6
20% = 30.12 (double it)
So 20% of $156 is $30.12
The answer will be 31 degrees
To solve this, you need to cross multiply the fractions.
Let’s say you have these fractions:
A / B = C / D
To cross multiply, multiply the denominator of the first fraction (B) by the numerator of the second fraction (C). Multiply the numerator of the first fraction (A) by the denominator of the second fraction (D).
You get B x C = A x D
After cross multiplying your fractions, you get 63 = 7(c +4)
Distributing the 7 into c+4 gives you this:
63 = 7c + 28
Now solve this like a normal equation with a variable
63 = 7c + 28
35 = 7c
5 = c
To double check that, plug c = 5 into the original equation.
1/(5) + 4 = 7/63
1/9 = 7/63
7/63 simplifies into 1/9 (7:7 = 1, 63/7 = 9)
1/9 = 1/9 so c = 5 is correct
Therefore (87)₁₀ = (1010111)₂
Take any base 10 number. Divide it by 2.