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3 years ago

12

If you combine the partial crates, how many additional full crates of oranges can be sold?

2 answers:

Natali [406]3 years ago

5 0

If you combine the partial crates, pending on how full and how many you have it will vary how many full crates of oranges can be sold.

Allisa [31]3 years ago

3 0

I think there is something that tells us how full the crates are, otherwise there's no way to solve this problem.
Let's assume that 5x oranges can fit into each crate, and that we have a crate with x oranges, a crate with 2x oranges, and a crate with 4x oranges. We get this:
x/5x+2x/5x+4x/5x
Add those together and we get
7x/5x
Turn it into a mixed number:
1 2x/5x
And we get our answer

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Which is the following fraction is the smallest?9/13 ,17/26, 28/39, 33/52

babunello [35]

Answer:

<h3>I THINK ITS A. 9/13 BECAUSE THE QUESTION SAID THAT FRACTION IS THE SMALLEST</h3>

Step-by-step explanation:

I HOPE IT HELPS :)

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3 years ago

What is the answer to 346*89? <br>Just a random question.

Licemer1 [7]

Answer:

346*89 would turn out to be 30794!

Step-by-step explanation:

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2 years ago

Read 2 more answers

Need help with these two question!!??

lawyer [7]

The measure of x in both parts is: 120°

Step-by-step explanation:

Part A:

We can clearly see that the figure in part a has six equal sides. So the given figure is a hexagon.

A hexagon has six equal sides in six equal interior angles.

Sum of interior angles of hexagon is 720°

So,

$Measure\ of\ one\ agnle=\frac{Sum\ of\ interior\ angles}{number\ of\ angles}\\=\frac{720}{6}\\=120$

Part B:

The figure is a Dodecagon with 12 sides.

The Dodecagon has 12 equal sides and angles.

The sum of internal angles of Dodecagon is 1440°

So,

$Measure\ of\ one\ angle=\frac{Sum\ of\ angles}{Number\ of\ angles}\\=\frac{1440}{12}\\=120$

The measure of x in both parts is: 120°

Keywords: Polygons, Hexagon

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#LearnwithBrainly

6 0

3 years ago

Blank plus 1/2 equals 8/10

Eduardwww [97]

Answer:

8/5

Step-by-step explanation:

Hope This Helps;)

8 0

3 years ago

Re-write the equation without the h component.

levacccp [35]

Answer:

$f(x) = 2[\frac{3^x}{9}] + 2$

$f(x) = 8(4)^x$

Step-by-step explanation:

Given

$f(x) = 2(3)^{x-2} + 2$

$f(x) = \frac{1}{2}(4)^{x+2}$

Required

Remove the h component

In a function, the h component is highlighted as:

$f(x) = a^{x+h}$

So, we have:

$f(x) = 2(3)^{x-2} + 2$

Split the exponents using the following law of indices:

$a^m/a^n = a^{m-n}$

$f(x) = 2*\frac{3^x}{3^2} + 2$

$f(x) = 2*\frac{3^x}{9} + 2$

$f(x) = 2[\frac{3^x}{9}] + 2$

<em>The h component has been removed</em>

$f(x) = \frac{1}{2}(4)^{x+2}$

Split the exponent using the following law of indices

$a^{m+n} =a^m * a^n$

So, we have:

$f(x) = \frac{1}{2}(4)^x * 4^2$

Express 4^2 as 16

$f(x) = \frac{1}{2}(4)^x * 16$

Divide 16 by 2

$f(x) = 8(4)^x$

3 0

3 years ago