If you combine the partial crates, how many additional full crates of oranges can be sold?

2 answers:

5 0

If you combine the partial crates, pending on how full and how many you have it will vary how many full crates of oranges can be sold.

Allisa [31]3 years ago

3 0

I think there is something that tells us how full the crates are, otherwise there's no way to solve this problem.
Let's assume that 5x oranges can fit into each crate, and that we have a crate with x oranges, a crate with 2x oranges, and a crate with 4x oranges. We get this:
x/5x+2x/5x+4x/5x
Add those together and we get
7x/5x
Turn it into a mixed number:
1 2x/5x
And we get our answer

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Read 2 more answers

1/2 + 5/3 - 1<br>------------------<br> 3/4

Sav [38]

Hey there :)

$\frac{ \frac{1}{2}+ \frac{5}{3} -1 }{ \frac{3}{4} }$
↓ Is the same as
$\frac{1}{2} + \frac{5}{3} -1$ ÷ $\frac{3}{4}$

Since it is a division by fraction, we can multiply by what is called the reciprocal
( The attached picture might help you )
( $\frac{1}{2} + \frac{5}{3} - 1$ ) × $\frac{4}{3}$
↓ For this part, we need the common denominator, which is 6
$\frac{1(3)}{2(3)}+ \frac{5(2)}{32)} \frac{1(6)}{1(6)}$ × $\frac{4}{3}$

$\frac{3}{6}+ \frac{10}{6} - \frac{6}{6}$ × $\frac{4}{3}$
$\frac{7}{6}$ × $\frac{4}{3}$
$\frac{14}{9} = 1\frac{5}{9}$
↑
Your final answer

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