Answer:
Verified
Step-by-step explanation:
Let the diagonal matrix D with size 2x2 be in the form of
![\left[\begin{array}{cc}a&0\\0&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%260%5C%5C0%26d%5Cend%7Barray%7D%5Cright%5D)
Then the determinant of matrix D would be
det(D) = a*d - 0*0 = ad
This is the product of the matrix's diagonal numbers
So the theorem is true for 2x2 matrices
Answer: 3log5(2) - 1 or ~0,29203
Step-by-step explanation:
2log5(4) - log5(10)
log5(4^2) - log5(10)
log5(4^2/10)
log5(16/10)
log5(8/5)
Log5(8) - log5(5)
log5(2^3) - 1
3log5(2) - 1
Answer: 
THE GRAPH IS ATTACHED.
Step-by-step explanation:
The Slope-Intercept form of the equation of a line is:
Where "m" is the slope of the line and "b" is the y-intercept.
In this case, you have the first equation:
You can identify that:
If you convert the Mixed number to a Decimal number, you get:
Then, knowing the slope and the y-intercept, you can graph the line.
The second equation is:
Solve for "y":
Knowing that:
You can graph the line.
The point of intersection between both lines, is the solution of the system. This is:
Observe the graph attached.
Answer:
The answer is option (C)=an-1+7
Step-by-step explanation:
A recursive rule is a formula that in which each term is expressed as a function of its preceding term(s), meaning in order to get to the nth term you have to express it in a form of the term that comes before it. In our case the a(n-1) term
So for the sequence -9, -2, 5, 12
The nth term is any number on the sequence and
- -2 is the a(n-1) term for -9
- 5 is the a(n-1) term for -2
- 12 is the a(n-1) term for 5
So we need to find out what we have to do to the preceding term to get the next.
To get -2 from -9 we have to add 7 to -9; -9+7=-2
To get 5 from -2 we have to add 7 to -2; -2+7=5
To get 12 from 5 we add 7 to 5; 7+5=12
So the recursive rule would be= a n-1+7
Answer:
Step 2
Step-by-step explanation:
I'm not that sure but I think that its right
