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3 years ago

Simplify: 6/10x^2 devided by 6/10x^3-60x^2

Mathematics

2 answers:

Alecsey [184]3 years ago

8 0

D. x-6
That is the correct answer.

goblinko [34]3 years ago

8 0

$\frac{6}{ {10x}^{2} } \div \frac{6}{10 {x}^{3} - 60 {x}^{2} } \\ = \frac{6}{10 {x}^{2} } \times \frac{10 {x}^{2} (x - 6)}{6} \\ = x - 6$

Answer is D.

Hope this helps. - M

P. S. If you have any question regarding this problem, feel free to pm me.

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How to solve (2x+8)^2

dusya [7]

You have to foil out the problem
(2x+8)(2x+8)
4x^2+16x+16x+64
4x^2+32x+64

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3 years ago

Determine by inspection (i.e., without performing any calculations) whether a linear system with the given augmented matrix has

devlian [24]

Answer:

Infinitely Many Solutions

Step-by-step explanation:

Given

$\left[\begin{array}{cccccc}1&2&3&4&5&6\\7&6&5&4&3&2\\8&8&8&8&8&8\end{array}\right]$

Required

Determine the type of solution

From the matrix, we have:

3 non-zero rows and 5 variables (the last column is the result)

When the number of variables is more than the number of non-zero rows, then such system has infinitely many solutions

i.e.

$Variables > Non\ zero\ rows$

$5 > 3$

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2 years ago

The U.S. Census Bureau conducts a study to determine the time needed to complete the short form. The Bureau surveys 200 people.

NISA [10]

Answer:

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8.2$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.2$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$8.2-2.58\frac{2.2}{\sqrt{18}}=6.86$

$8.2+2.58\frac{2.2}{\sqrt{18}}=9.54$

So on this case the 90% confidence interval would be given by (6.86;9.54) And the error is given by:

$ME= 2.58\frac{2.2}{\sqrt{18}} =1.338$

8 0

3 years ago

Read 2 more answers

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3 years ago

What is the measure of the lowercase c?

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The measure of angle c would be 84

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2 years ago