This will be:
[√9]/[(3-2i)+(1+5i)]
simplifying the above we get:
√9/(3+1-2i+5i)
=√9/(4+3i)
rationalizing the denominator we get:
√9/(4-3i)×(4-3i)/(4-3i)
=[√9(4-3i)]/(16+9)
=[3(4-3i)]/25
=(12-9i)/25
Answer: (12-9i)/25
Answer:
I think it is B) 0
Step-by-step explanation:
Oof I’m gonna fail hard body what is this jibberish
●) -2 (3a - 4b)-6a + 3b
-2 (9a-7b)
●) 10 - 6a - 4y - (-2a) + 9y
10 - 6a - 13y - (-2a)
●) 9 (2x-6) - 3 (5-4x
12 (6x-11)
All I did was combine the numbers with the same variable
Answer: subtraction property
x-(-6)=18
x+6=18
Subtract 6 from both sides
And you get x=12
