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galben [10]
2 years ago
10

I forgot the unit rate of $6.25 for 5lbs. of apples

Mathematics
1 answer:
VladimirAG [237]2 years ago
5 0
$6.25 is the cost of 5 lbs. of apples. Here the question is 'what is the cost of 1 lb of apple?' To find the unit rate or the cost of 1 lb of apple, divide the sum by the given quantity. The sum is @6.25 and the given quantity is 5 lbs. So the unit rate = 6.25/5 = $1.25
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Jamal has been approved for $125,000 loan, 30-year mortgage with an APR of 5.3%. He made a 10% down payment and is closing on Ap
Alex17521 [72]

Answer:

Step-by-step explanation:

Loan APR is 5.535%

Loan information:

Mortgage amount:

$125,000

Term in years:

Interest rate:

5.3%

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3 years ago
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Can anyone help me with this question?
Leona [35]

Answer:

25x

Step-by-step explanation:

25 divide by 6

7 times 8

12x+y4 equals 276 divided by 25

Answer_ 25x

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3 years ago
Find the volume of the composite figure. Give your answer in terms of pi.
Sloan [31]
Volume of cone= 1/3 πr²*h
15²=10²+h²
h²=15²-10²=125
h=√125
Volume of cone= 1/3 *π*100*√125=π/3*(100*5√5)=500π√5/3
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7 0
3 years ago
The Board of Directors of a small company consists of five people. Two of those directors are considered "strong leaders". If th
Pavel [41]
1: 40%
2: 30%
3: 20%

If we know one of the succeeded, then 
1: 44.44%
2: 33.33%
3: 22.22%

If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%

The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.

1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
7 0
3 years ago
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
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