Answer:
Step-by-step explanation:
Loan APR is 5.535%
Loan information:
Mortgage amount:
$125,000
Term in years:
Interest rate:
5.3%
Monthly payment:$694.13
Answer:
25x
Step-by-step explanation:
25 divide by 6
7 times 8
12x+y4 equals 276 divided by 25
Answer_ 25x
Volume of cone= 1/3 πr²*h
15²=10²+h²
h²=15²-10²=125
h=√125
Volume of cone= 1/3 *π*100*√125=π/3*(100*5√5)=500π√5/3
Volume of sphere=4/3*π*r³=4/3*π*1000=4000π/3
Volume of half sphere=(4000π/3)/2=2000π/3
All Volume=500π√5/3+2000π/3
1: 40%
2: 30%
3: 20%
If we know one of the succeeded, then
1: 44.44%
2: 33.33%
3: 22.22%
If under the circumstance that they all fail to meet a strong leader, the board picks one of them at random,
1: 43.33%
2: 33.33%
3: 23.33%
The first person has a 2 in 5 chance of randomly getting a strong leader. If the first person doesn't find a strong leader, the second person has a 2/4 chance of getting a strong leader. If neither the first nor second person gets a strong leader, the third sales person has a 2/3 chance of getting a strong leader.
1: 2/5=40% Chance
2: (3/5)*(2/4)=30% Chance You have to take the probability the first rep failed to get a strong leader, then multiply by the probability the second rep gets a strong leader.
3: (3/5)*(2/4)*(2/3)=20% You have to take the probability both the other people failed, then multiply by the probability they succeeded.
Answer:
t = 460.52 min
Step-by-step explanation:
Here is the complete question
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.
Solution
Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.
inflow = 0 (since the incoming water contains no dye)
outflow = concentration × rate of water inflow
Concentration = Quantity/volume = Q/200
outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.
So, Q' = inflow - outflow = 0 - Q/100
Q' = -Q/100 This is our differential equation. We solve it as follows
Q'/Q = -1/100
∫Q'/Q = ∫-1/100
㏑Q = -t/100 + c

when t = 0, Q = 200 L × 1 g/L = 200 g

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

㏑0.01 = -t/100
t = -100㏑0.01
t = 460.52 min