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anastassius [24]
3 years ago
13

III

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

120km/h

600km in 5 hours.

Step-by-step explanation:

1000 meters is equal to 1 kilometer. 1 meter is equal to .001 kilometer.

You can set up an equation like this to solve for the car's rate in kilometers.

\frac{1 km}{1000 m} = \frac{x km}{35m}  or  \frac{1000 m}{1000 km} = \frac{x m}{35km}.

Now crossmultiply either fraction to solve for x.

\frac{1 km}{1000 m} = \frac{x km}{35m}\\\frac{1 km}{1000 m}*35 = \frac{x km}{35m}*35\\\frac{35 km}{1000 m} = xkm

The car is going at .035km/sec. Now we need to multiply this to get kilometers per hour. There are 60 seconds in a minute and there are 60 minutes in a hour.

\frac{35}{1000} * 60 * 60

The car travels at 120km per hour.

Since we now know the rate in kilometers per hour. We can multiply the rate by 5 since the question asks how many kilometers the car will travel in 5 hours.

120 * 5 = 600

The car will travel 600km in 5 hours.

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4 years ago
The difference of a number divided by 7 and 9 is equal to 2. use the variable C what the unknown
bogdanovich [222]
Given that the number is C.
The number divided by 7 is C/7
Difference means we will subtract 9 from C/7.
Therefore, the equation will be:
C/7 - 9 = 2 (multiply all terms by 7 to get rid of the fraction)
C - 63 = 14
C = 14 + 63 = 77
5 0
3 years ago
Find the value of annuity if the periodic deposit is $250 at 5% compounded quarterly for 10 years
mylen [45]

Answer:

The value of  annuity is  P_v  =  \$ 7929.9

Step-by-step explanation:

From the question we are told that

    The periodic payment is  P  =  \$ 250

     The  interest rate  is   r =  5\%  =  0.05

     Frequency at which it occurs in a year is  n = 4 (quarterly )

      The number of years is  t =  10 \ years

The  value of the annuity is mathematically represented as

             P_v  =  P *  [1  - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ] (reference EDUCBA website)

 substituting values

             P_v  = 250 *  [1  - (1 + \frac{0.05}{4} )^{-10 * 4} ] * [\frac{(1 + \frac{0.05}{4} )}{ \frac{0.08}{4} } ]

             P_v  =  250 *  [1  - (1.0125 )^{-40} ] * [\frac{(1.0125 )}{0.0125} ]

             P_v  =  250 *  [0.3916 ] * [\frac{(1.0125)}{0.0125} ]

            P_v  =  \$ 7929.9

8 0
3 years ago
Consider the trapezoid with given dimensions. Suppose it is dilated by a scale factor of
koban [17]

Answer: 1 & 4

Step-by-step explanation:

Just did it

6 0
3 years ago
Find the sum of first 15 terms of an AP whose 4th and 9th t terms are -15 and -30 respectively.
Serga [27]

Answer:

Sum of the first 15 terms = -405

Step-by-step explanation:

a + 3d = -15 (1)

a + 8d = -30 (2)

Where,

a = first term

d = common difference

n = number of terms

Subtract (1) from (1)

8d - 3d = -30 - (-15)

5d = -30 + 15

5d = -15

d = -15/5

= -3

d = -3

Substitute d = -3 into (1)

a + 3d = -15

a + 3(-3) = -15

a - 9 = -15

a = -15 + 9

a = -6

Sum of the first 15 terms

S = n/2[2a + (n − 1) × d]

= 15/2 {2×-6 + (15-1)-3}

= 7.5{-12 + (14)-3}

= 7.5{ -12 - 42}

= 7.5{-54}

= -405

Sum of the first 15 terms = -405

7 0
3 years ago
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