D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
You take 60 and divide it by 10 which is 6 so the height would be 6
Answer:
x-int : 6, y-int : 9
Step-by-step explanation:
Hope this helps :)
Let me know if you want a full explanation
Answer:
do you have an image for that?
Step-by-step explanation:
