Question

URGENT! WILL GIVE BRAINLIEST!!

Answer 1

Answer:

Option C

Step-by-step explanation:

It is given that (m + b), (2m + b), (3m + b), (4m + b)...... is an infinite sequence.

To check the correct way to define the sequence we will check each option given.

Option A.

f(x) = mx + b,      x = {1, 2, 3.....}

So the sequence formed by placing x = {1, 2, 3.....}

f(1) = m + b

f(2) = 2m + b

So this option is not the answer.

Option B.

f(x) = 2m + b + m(x - 2) for x = {1, 2, 3,........}

f(1) = 2m + b + m(1 - 2)

    = 2m + b - m

    = m + b

Which is our sequence.

Therefore, this option is not correct.

Option C.

$a_{n}=m-b+m(n-1)$ for n = {1, 2, 3, ........}

$a_{1}=m-b+m(1-1)$

    = m - b

Which is not our sequence.

Therefore, this is the correct option which is not the correct way to define the given sequence.

Option D.

$a_{1}=m+b$ and $a_{n+1}=a_{n}+m$ for n = {1, 2, 3......}

$a_{2}=a_{1}+m$

    = m + b + m

    = 2m + b

So, this option is also incorrect.

Therefore, Option C is the answer.

Answer 2

Answer:

C) an = m − b + m(n − 1) for n = {1, 2, 3, ...}

Step-by-step explanation:

Nevermind you dont gotta tell me nothin. I just guessed and got C right. lol.