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3 years ago

Evaluate x/y + 3z^2 for x= 2/3, y= 6/7, and z=3

2 answers:

7 0

remember that (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

(2/3)/(6/7)+3(3)^2=
(2/3)(7/6)+3(9)=
(2*7)/(3*6)+27=
(14/18)+27=
(7/9)+27=
7/9+243/9=
250/9

answer is A

prohojiy [21]3 years ago

6 0

x/y + 3z^2 for x= 2/3, y= 6/7, and z=3

=2/3 / 6/7 + 3(3^2)

=2/3 * 7/6 + 3(9)

= 7/9 + 27

= 7/9 + 243/9

= 250/9

answer is a. 250/9

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Which of the following could be points on the unit circle: A. (4/3, 4/5) B. (5/13, 12/13)

IRINA_888 [86]

Answer:

Option (2) and (4) are correct.

$(\frac{5}{13},\frac{12}{13} )$ and $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ are points on the unit circle.

Step-by-step explanation:

Given : Some points of circles.

We have to choose which points could be points on the unit circle.

We know, the equation of circle is

$x^2+y^2=r^2$ ..........(1)

where r is radius of circle.

We check each point for x and y values on the equation of circle and see which point gives radius = 1

Thus,

1) $(\frac{4}{3},\frac{4}{5} )$

Put in LHS of (1) , we have,

$(\frac{4}{3})^2+(\frac{4}{5})^2$

Simplify, we have,

$=\frac{16}{9}+\frac{16}{25}$

$=\frac{544}{225}\neq 1$

Thus, $(\frac{4}{3},\frac{4}{5} )$ is not a point on the unit circle.

2) $(\frac{5}{13},\frac{12}{13} )$

Put in LHS of (1) , we have,

$(\frac{5}{13})^2+(\frac{12}{13})^2$

Simplify, we have,

$=\frac{25}{169}+\frac{144}{169}$

$=\frac{169}{169}= 1$

Thus, $(\frac{5}{13},\frac{12}{13} )$ is a point on the unit circle.

3) $(\frac{1}{3},\frac{2}{3} )$

Put in LHS of (1) , we have,

$(\frac{1}{3})^2+(\frac{2}{3})^2$

Simplify, we have,

$=\frac{1}{9}+\frac{4}{9}$

$=\frac{5}{9}\neq 1$

Thus, $(\frac{1}{3},\frac{2}{3} )$ is not a point on the unit circle.

4) $(\frac{6}{7},\frac{\sqrt{13}}{7} )$

Put in LHS of (1) , we have,

$(\frac{6}{7})^2+(\frac{\sqrt{13}}{7})^2$

Simplify, we have,

$=\frac{36}{49}+\frac{13}{49}$

$=\frac{49}{49}= 1$

Thus, $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ is a point on the unit circle.

Thus, $(\frac{5}{13},\frac{12}{13} )$ and $(\frac{6}{7},\frac{\sqrt{13}}{7} )$ are points on the unit circle.

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a quarter horse can run 53.16 mile per hour. a garden snail moves at 0.02 miles per hour. how much faster is the quarter horse t

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Answer:

53.14

Step-by-step explanation:

Subtract 0.02 from 0.06 and you get 0.04

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a court reporter is transcribing an accident report the report states that the driver was traviling 110km per hour how many mile

Vera_Pavlovna [14]

Answer:

The driver was traveling at approximately 68.2 miles per hour

Step-by-step explanation:

Recall that one km equals approximately 0.62 miles, therefore, in order to find the speed of the driver in miles per hour, we just need to convert the 110 km into miles.

if one km equals 0.62 miles, then 110 km will equal the product of 110 times 0.62 miles. That is:

110 * 0.62 = 68.2 miles

Then the speed will translate into :

110 km/h = 68.2 mi/h

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Find the aspect ratio of a computer screen that measures 12 inches by 16 inches.

alexdok [17]

Answer:

3:4

Step-by-step explanation:

That ratio would be 12:16, or 3:4.

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