What is (1 2/3) divided by (1/8)? A)12 B)13 1/3 C)4 4/5 D)5/24

Multiply. express your anwser in simplist form.. 1 7\8 × 2 1\3

AnnyKZ [126]

Answer:

4 and 3/8

Step-by-step explanation:

5 0

3 years ago

Help pls I’ll give u BARINLIEST

e-lub [12.9K]

Answer:

the ratio is 1 : 1.75

Step-by-step explanation:

8 0

3 years ago

48% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually

oksian1 [2.3K]

Answer:

There is no sufficient evidence to support the executive claim

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.48$

The sample proportion is $\r p = 0.45$

The sample size is $n = 300$

The level of significance is $\alpha = 0.02$

The null hypothesis is $H_o : p= 0.48$

The alternative hypothesis is $H_a : p \ne 0.48$

Generally the test statistics is mathematically evaluated as

$t = \frac{\r p - p }{ \sqrt{ \frac{p(1 - p )}{n} } }$

=> $t = \frac{0.45 - 0.48 }{ \sqrt{ \frac{0.48 (1 - 0.48 )}{300} } }$

=> $t = -1.04$

The p-value is mathematically represented as

$p-value = 2P(z > |-1.04|)$

Form the z-table

$P(z > |-1.04|) = 0.15$

=> $p-value = 2 * 0.15$

=> $p-value = 0.3$

Given that $p-value > \alpha$ we fail to reject the null hypothesis

Hence we can conclude that there is no sufficient evidence to support the executive claim

5 0

3 years ago

A cake is removed from a 310°F oven and placed on a cooling rack in a 72°F room. After 30 minutes the cake's temperature is 220°

Fynjy0 [20]

Answer:

The time is 135 min.

Step-by-step explanation:

For this situation we are going to use Newton's Law of Cooling.

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium and is given by

$T(t)=C+(T_0-C)e^{kt}$

where,

C = surrounding temp

$T(t)$ = temp at any given time

t = time

$T_0$ = initial temp of the heated object

k = constant

From the information given we know that:

Initial temp of the cake is 310 °F.
The surrounding temp is 72 °F.
After 30 minutes the cake's temperature is 220 °F.

We want to find the time, in minutes, since the cake's removal from the oven, at which its temperature will be 100°F.

To do this, first, we need to find the value of k.

Using the information given,

$220=72+(310-72)e^{k\cdot 30}\\\\72+238e^{k30}=220\\\\238e^{k30}=148\\\\e^{k30}=\frac{74}{119}\\\\\ln \left(e^{k\cdot \:30}\right)=\ln \left(\frac{74}{119}\right)\\\\k\cdot \:30=\ln \left(\frac{74}{119}\right)\\\\k=\frac{\ln \left(\frac{74}{119}\right)}{30}$

$T(t)=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}$

Next, we find the time at which the cake's temperature will be 100°F.

$100=72+(310-72)e^{(\frac{\ln \left(\frac{74}{119}\right)}{30}\cdot t)}\\72+238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=100\\238e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=28\\e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}=\frac{2}{17}\\\ln \left(e^{\frac{\ln \left(\frac{74}{119}\right)}{30}t}\right)=\ln \left(\frac{2}{17}\right)\\\frac{\ln \left(\frac{74}{119}\right)}{30}t=\ln \left(\frac{2}{17}\right)\\t=\frac{30\ln \left(\frac{2}{17}\right)}{\ln \left(\frac{74}{119}\right)}\approx 135.1$

4 0

3 years ago

Solve for x. Show your work. - x < -12

Andrej [43]

All you have to do is move -x to the right side and -12 to the left side to remove the negative sign.
-x<-12 (Original)
0<-12+x (Add x to both sides)
12<x (Add 12 to both sides)
The answer is 12<x, or you can write it as x>12.

8 0

4 years ago