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sergiy2304 [10]
4 years ago
10

Explain how to check if your solution to an equation is correct

Mathematics
1 answer:
diamong [38]4 years ago
8 0
Hope this helps you!

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A square of side x is cut out of a larger square of side y. What is the area of the remaining
KonstantinChe [14]

Answer:

The area of the remaining figure is y^2-x^2

Step-by-step explanation:

<u>Area of the Square Shape</u>

Given a square of side length x, the area is calculated by the formula:

A_x=x^2

It's given a square of side x is cut out of a larger square of side y. Please refer to the image below.

The area of the square of side length y is:

A_y=y^2

The shaded area of the remaining figure is the difference between both areas:

A=A_y-A_x

A=y^2-x^2

The area of the remaining figure is \mathbf{y^2-x^2}

3 0
3 years ago
To get a 100 kilograms of a 48% fat content chocolate how many kilograms of a 30% and 50% mix should be used
wlad13 [49]
A kilogram %30 chocolate,
b kilogram %50 chocolate,
a+b = 100 kilogram chocolate,

48.(a+b) = 30.a + 50.b
48a + 48b = 30a + 50b
18a = 2b
b = 9a

a+b = a + 9a = 10a = 100 kg
a = 10 kg
b = 9.a = 90 kg

You should use,

10 kg %30 chocolate,
90 kg %50 chocolate
8 0
4 years ago
Simplify the following
irga5000 [103]

\huge\fbox{Answer ☘}

\bold\blue{( - 8z) {}^{2} } \\\bold{  =  > 64z {}^{2} }

hope helpful~

8 0
3 years ago
Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient
JulsSmile [24]

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0

when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

7 0
3 years ago
What is equivalent form of the expression 15x + 24ax
neonofarm [45]
15x + 24ax = 3x(5+8a)
3 0
3 years ago
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