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3 years ago

Explain how to check if your solution to an equation is correct

Mathematics

1 answer:

diamong [38]3 years ago

8 0

Hope this helps you!

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Explain how to form a linear combination to eliminate the variable y for this system. 2x - 3y = 3 5x + 2y = 17A)Multiply the fir

jonny [76]

We aer goint to eliminate the x's
multiply first by -5 and 2nd by 2
so that is B

7 0

3 years ago

Can someone solve this equation -101=7+3(-4t4n)

alex41 [277]

The answer should be n=-8

5 0

3 years ago

Read 2 more answers

Question 6

Tema [17]

Answer:

Actual volume = 40 cm^3.

Step-by-step explanation:

15% = 0.15 as a decimal fraction.

Let the actual volume be x cm^3, then we have the equation:

x + 0.15x = 46

1.15x = 46

x = 46 / 1.15

= 40 cm^3.

7 0

2 years ago

5 years ago, my grandfather was five times as old as I was. Three years from now, my grandfather will be three times as old as I

balu736 [363]

<h3>Answer:</h3>

13 years old

<h3>Explanation:</h3>

Let g and m represent grandfather's age now and my age now. The relation 5 years ago was ...

... g -5 = 5(m -5)

The relation in 3 years will be ...

... g +3 = 3(m +3)

Subtracting the first equation from the second, we get ...

... 8 = -2m +34

... 2m = 26 . . . . . add 2m-8

... m = 13

My age now is 13.

4 0

2 years ago

Read 2 more answers

Show me how you solve it

julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

Law of Exponent I

$\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} }$

Therefore:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} }$

Law of Exponent II

$\displaystyle \large{( {a}^{m} ) ^{n} = {a}^{m \times n} }$

Thus:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{5 \times 4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{20} }$

7 0

2 years ago