What is the volume of a cube

How to write a repeating decimal as a fraction

ankoles [38]

Step 1: Write down the decimal divided by 1, like this:

decimal

1

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

Step 3: Simplify (or reduce) the fraction

7 0

4 years ago

at least $580 to buy a new Bose sound system. He has $210 in savings and plans to save $30 a week until he has enough money to b

rusak2 [61]

Answer:

13 weeks

Step-by-step explanation:

multiply $30 by 13 weeks you get $390 add the $210 and get $600

4 0

4 years ago

Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student

AysviL [449]

Answer:

The mean calculated for this case is $\bar X=584$

And the 95% confidence interval is given by:

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=584$

The sample deviation calculated $s=86.776$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$584-2.776\frac{86.776}{\sqrt{5}}=476.271$

$584+2.776\frac{86.776}{\sqrt{5}}=691.729$

So on this case the 95% confidence interval would be given by (476.271;691.729)

3 0

3 years ago

La densidad de un líquido es de 1.5 gr/cm3 su masa es de 7 libras Determina la cantidad de litros que ocupan dichos líquidos

egoroff_w [7]

Answer:

La cantidad de litros que ocupa dicho líquido es:

2,12 Litros

Step-by-step explanation:

El volumen de un líquido puede obtenerse al tener tanto su densidad como su masa usando la siguiente fórmula:

Densidad = masa / volumen

Al despejar volumen se obtiene:

Volumen = masa / densidad

Por lo cual, si se reemplazara la fórmula quedaría:

Volumen = 7 Lb / 1.5 gr/cm^3

Sin embargo, para operar, las unidades en las que se expresa la masa deben coincidir con las unidades de la densidad, por lo cual vamos a convertir las libras en gramos teniendo en cuenta el siguiente factor de conversión:

1 libra = 453,592 gramos

Entonces:

7 lb = 453,592 gr * 7 = 3175,144 gr

Ahora este valor reemplaza la masa en la fórmula y calculamos:

Volumen del líquido = 3175,144 gr / 1.5 gr/cm^3

Volumen del líquido = 2116,762667 cm^3 (He utilizado todos los decimales para obtener el resultado exacto).

A simple vista ya se tiene el volumen del líquido en cuestión, sin embargo, el ejercicio pide que sea expresado en litros, por lo cual vamos a convertir los centímetros cúbicos en litros teniendo en cuenta el siguiente factor de conversión:

1 litro = 1000 centímetros cúbicos.

Ahora podemos aplicar una regla de tres simple, si:

1000 cm^3 = 1 L
2116,762667 cm^3 = x

Y operamos:

x = (2116,762667 cm^3 * 1 L) / 1000 cm^3
x = 2,116762667 L

O si quieres un valor aproximado:

x = 2,12 Litros.

Entonces, la cantidad de litros teniendo en cuenta la densidad y la masa brindadas es 2,12 litros.

8 0

3 years ago

What are two division expressions that have the same value as 61.12 divided by 3.2

slavikrds [6]

122.24 divided by 6.4

And

30.56 divided by 1.6

4 0

4 years ago

Read 2 more answers