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Goryan [66]
3 years ago
13

What is the perimeter of the polygon?

Mathematics
1 answer:
mr_godi [17]3 years ago
6 0
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B




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butalik [34]
Let
A-----> the point (0.25,1)
B-----> the point (0.50,1.75)

we know that
the equation that represents the linear function is the equation of a line
so
step 1
find the slope m with the points A and B
m=(y2-y1)/(x2-x1)-----> m=(1.75-1)/(0.50-0.25)---> m=0.75/0.25--> m=3

step 2
with m=3 and point A (0.25,1)
 find the equation of a line
y-y1=m*(x-x1)-------> y-1=3*(x-0.25)----> y=3x-0.75+1----> y=3x+0.25

the answer is
y=3x+0.25

see the attached figure

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Answer:

              \bold{x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\quad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7}

Step-by-step explanation:

-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7

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