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3 years ago

PLEASSSEEEE HELPPPP

Mathematics

1 answer:

scoray [572]3 years ago

3 0

Answer:

23,11333753

Step-by-step explanation:

1. Use The Coordinates To Find The Distances Of The Four Sides

2. The Formula For Perimeter Or A Quad =

AB + BC + CD + AD

Basically Add The Distances Of The Four Sides

So: WX + XY + YZ + WZ

$\sqrt{34} + 5 + \sqrt{61} + 2 \sqrt{5}$

= 23,11333753

.°. 23,1

b.????

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What is the probability that a fair die never comes up an even number when it is rolled six times? (note: enter the value of pro

seropon [69]

Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:

Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.

Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64

Therefore, the probability is 1/64 or 1.56%.

6 0

4 years ago

A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0

3 years ago

A rectangular dining room table top is 36 inches wide the diagonal to tabletop measures 85 inches how many inches long is a tabl

makvit [3.9K]

Pythagorean theorem: a^2 + b^2 = c^2
36^2 + b^2 = 85^2
1296 + b^2 = 7225
b^2 = 7225 - 1296
b^2 = 5926
b = square root of 5929
b = 77 inches long

6 0

3 years ago

Please help please !!!

Kobotan [32]

<h3>Answer: 12</h3>

========================================================

Explanation:

You can use the AAS (angle angle side) theorem to prove that triangle ABD is congruent to triangle CBD.

From there, we can then say that AD and DC are the same length

AD = DC

3y+6 = 5y-18

3y-5y = -18-6

-2y = -24

y = (-24)/(-2)

y = 12

6 0

3 years ago

I need help lol. Find the lateral surface area of the figure to the nearest tenth.

Mekhanik [1.2K]

Answer:

101.9 sq ft

Step-by-step explanation:

The figure is missing: find it in attachment.

Here we want to find the lateral surface area of the figure, which is the sum of the areas of all faces.

We have in total 5 faces:

- 1 of them is rectangle with sizes (8.5 ft x 3.3 ft), so its area is

$A_1=8.5 \cdot 3.3 =28.1 ft^2$

- 1 of them is a rectangle with sizes (3.3 ft x 5.1 ft), so its area is

$A_2 = 3.3\cdot 5.1 =16.8 ft^2$

- 1 of them is a rectangle with sizes (6.8 ft x 3.3 ft), so its area is

$A_3 = 6.8\cdot 3.3 =22.4 ft^2$

- Finally, we have 2 triangular faces (top and bottom), so their area is

$A_T=\frac{1}{2}bh$

where

b = 5.1 ft is the base

h = 6.8 ft is the height (because the triangle is a right triangle)

So the area of the triangle is

$A_T=\frac{1}{2}(5.1)(6.8)=17.3 ft^2$

So the total lateral surface area of the figure is:

$A=A_1+A_2+A_3+2A_T=28.1+16.8+22.4+2(17.3)=101.9 ft^2$

5 0

4 years ago