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scoray [572]
2 years ago
6

PLEASSSEEEE HELPPPP

Mathematics
1 answer:
scoray [572]2 years ago
3 0

Answer:

23,11333753

Step-by-step explanation:

1. Use The Coordinates To Find The Distances Of The Four Sides

2. The Formula For Perimeter Or A Quad =

AB + BC + CD + AD

Basically Add The Distances Of The Four Sides

So: WX + XY + YZ + WZ

\sqrt{34}  + 5 +  \sqrt{61}  +  2 \sqrt{5}

= 23,11333753

.°. 23,1

b.????

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
Ugo [173]

Answer:

Side\ B = 6.0

\alpha = 56.3

\theta = 93.7

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with \alpha, \beta, \theta

[See Attachment for Triangle]

A = 10cm

C = 12cm

\beta = 30

What the question is to calculate the third length (Side B) and the other 2 angles (\alpha\ and\ \theta)

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

B^2 = A^2 + C^2 - 2ABCos\beta

Substitute: A = 10,  C =12; \beta = 30

B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30

B^2 = 100 + 144 - 240*0.86602540378

B^2 = 100 + 144 - 207.846096907

B^2 = 36.153903093

Take Square root of both sides

\sqrt{B^2} = \sqrt{36.153903093}

B = \sqrt{36.153903093}

B = 6.0128115797

B = 6.0 <em>(Approximated)</em>

Calculating Angle \alpha

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute: A = 10,  C =12; B = 6

10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 36 + 144 - 144 *Cos\alpha

100 = 180 - 144 *Cos\alpha

Subtract 180 from both sides

100 - 180 = 180 - 180 - 144 *Cos\alpha

-80 = - 144 *Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}

\frac{-80}{-144} = Cos\alpha

0.5555556 = Cos\alpha

Take arccos of both sides

Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)

Cos^{-1}(0.5555556) = \alpha

56.25098078 = \alpha

\alpha = 56.3 <em>(Approximated)</em>

Calculating \theta

Sum of angles in a triangle = 180

Hence;

\alpha + \beta + \theta = 180

30 + 56.3 + \theta = 180

86.3 + \theta = 180

Make \theta the subject of formula

\theta = 180 - 86.3

\theta = 93.7

5 0
3 years ago
What is the value of x which proves that the runways are parallel? What is the measure of the larger angle?
makkiz [27]

Answer:

118°

Step-by-step explanation:

When two parallel lines are cut by a tranversal, then the exterior angles are supplimentary and the corresponding angles are congruent.

Therefore the angle above (15x - 17)° is also (5x + 17)° and the angle below (5x + 17)° is also (15x - 17)°.

Angles on a straight line adds up to 180°. So to know the measure of the larger angle we must both equations and equal it to 180° to find x in order to know the larger angle.

(5x + 17) + (15x - 17) = 180

5x + 15x + 17 - 17 = 180

20x = 180

20x/20 = 180/20

x = 9°

Nkw let's substitute x = 9 into the equations

5x + 17 =

5(9) + 17 =

= 62°

15x - 17 =

15(9) - 17 =

= 118°

Both equations should add up to be 180°.

Therefore the measure of the largest angle is 118°.

6 0
3 years ago
Find g(4x)<br> g(x)=x²-4
7nadin3 [17]

Answer:

g(x) = x² - 4 is already in form of a variable, I.e., x

g(4x) takes another variable, I.e., 4x

Same as before, 4x takes over x:

=> g(4x) = (4x)² - 4

  • <em>(</em><em>ax</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>a</em><em>²</em><em>x</em><em>²</em><em>,</em><em> </em><em>where</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>some</em><em> </em><em>arbitrary</em><em> </em><em>constant</em><em>.</em><em> </em>

<h3><u>Answer</u><u>:</u> </h3>

=> g(4x) = 16x² - 4

OR

=> g(4x) = 4{4x² - 1}

3 0
2 years ago
Read 2 more answers
Need help quick please
Travka [436]

Answer:

line 2

Step-by-step explanation:

on line 2 the two minuses at the end turn into a + (where the -2 is there should be a +2) because - x - = +

4 0
3 years ago
PLEASE HELP!!!
Art [367]
<h3>Answer: B. About 93%</h3>

You have the correct answer.

=======================================================

Explanation:

Focus solely on the "in anime club" row. We do this because of the phrasing "given the student is in the anime club". We know for a fact that whoever is randomly picked, they are in the anime club. So we don't have to worry about other data values in the other rows.

Divide the value 0.13 which is in the "takes Japanese" column over 0.14, which is in the "total" column.

Basically we're computing P(A|B) = \frac{P(A \cap B)}{P(B)} where A and B represent the events "takes Japanese" and "in anime club" respectively. The upside down U symbol represents intersection to indicate both events are happening at the same time.

So we end up with 0.13/0.14 = 0.92857142857142 which rounds to 0.93, then that converts to 93% when you move the decimal point over to the right two spots.

7 0
3 years ago
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