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3 years ago

Chloe has 26 1/4 yards of ribbon to wrap presents. She needs 3 3/4 yards for each present. How many presents can Chloe wrap?

Mathematics

1 answer:

Mashcka [7]3 years ago

3 0

Chloe could wrap 7 presents

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each year the gardners plant 7/8 of an acre with tomatoes. They sell half of what they grow at a roadside stand. What part of an

Yakvenalex [24]

$\frac78\ \cdot\ \frac12=\frac{7}{16}$

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3 years ago

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I will mark you as the brainiest if you get this correct<br> Thx so much xxx

solong [7]

Answer:

A= 168 minutes or 2 hours and 48 minutes.

B= 3 tyres

Step-by-step explanation:

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2 years ago

a towns population has been decreasing at a constant rate. In 2007 the population was 5100. by 2011 the population had dropped t

Gelneren [198K]

75, because 300 (5100-4800) divided by 4 ( 2007-2011) is 75. The towns population decreased at a constant rate of 75.

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3 years ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

$\frac{dm}{dt} = -k\cdot m$

b) The general solution is found after separating variables and integrating each sides:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $\tau$ is the time constant and $k = \frac{1}{\tau}$

c) The time constant is:

$\tau = \frac{1690\,yr}{\ln 2}$

$\tau = 2438.155\,yr$

The particular solution of the differential equation is:

$m(t) = 10\cdot e^{-\frac{t}{2438.155} }$

d) The amount of radium after 300 years is:

$m(300) \approx 8.842\,g$

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3 years ago

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Which expression represents, six times a number plus 8 times a number?

Arada [10]

6a+8b; when a variable is next to a coefficient then that means they are multiplying each other, we just don't know what a or b is.

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3 years ago

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