All categories

3 years ago

Chloe has 26 1/4 yards of ribbon to wrap presents. She needs 3 3/4 yards for each present. How many presents can Chloe wrap?

Mathematics

1 answer:

Mashcka [7]3 years ago

3 0

Chloe could wrap 7 presents

You might be interested in

A hot air balloon climbs, at a 30 degree angle to the ground, to a height of 800 feet. To the nearest tenth of a foot, what grou

Sliva [168]

It would be 300 feet of 3 dergree

6 0

3 years ago

Click

Mama L [17]

Answer:

(-3 , 0) (0, 2) (6, -6)

Step-by-step explanation:

Solving for x - intercept:

2x - 3(0) = -6

2x = -6

2x/2 = -6/2

x = -3

One point would be (-3 , 0) .

Solving for y-intercept:

2(0) - 3y = -6

-3y = -6

-3y/-3 = -6/-3

y = 2

Another point would be (0, 2).

When 'x' equals 6:

2(6) - 3y = -6

12 - 3y = -6

12 - 12 - 3y = -6 - 12

-3y = -18

-3y/3 = -18/3

y = -6

The third point would be (6, -6).

6 0

3 years ago

8) An extremely handsome math teacher is on African

viva [34]

Answer:

One less zebra

Step-by-step explanation:

T z l

0 200 220

1 160 175 (subtract 40 from 200 and 45 from 220)

2 120 130

3 80 85

4 40 = 40 <===== lion has zebra lunch before the river is reached

Zdistance = 200 - 40s

Ldistance = 220 - 45 s where 's' is seconds

8 0

2 years ago

Can someone please help me with this ?

serg [7]

Answer:

Area = 25 cm²

Diagonal = 10.6cm

8 0

2 years ago

A researcher wishes to estimate, with 9090% confidence, the proportion of adults who have high-speed Internet access. Her es

Sunny_sXe [5.5K]

Answer: a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : $z_{\alpha/2}=1.645$

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219$

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271$

Required minimum sample size= 271

8 0

2 years ago