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3 years ago

Uhhhh last question lol I have to match them

Mathematics

2 answers:

harkovskaia [24]3 years ago

6 0

5-35n
-6x-24
15m-30
24p-28
5b-5
5x+45
Hope this is helpful:D

Anarel [89]3 years ago

4 0

Answer:

7. is 5 - 35n

8. is -6x - 24

9. is 15m - 30

10. is 24p - 28

11. is 5b - 5

12. 5x + 45

RULE:

WHEN MULTIPLYING TWO NEGATIVES YOU WILL GET POSITIVE.

IF ONE IS NEGATIVE AND THE OTHER IS POSITIVE WHEN MULTIPLYING IT WILL BE NEGATIVE.

WHEN MULTIPLYING TWO POSITIVE NUMBERS IT WILL ALWAYS BE POSITIVE

SAME THING IF YOU MULTIPLY A POSITIVE NUMBER WITH A NEGATIVE NUMBER YOU GET A NEGATIVE AS YOUR ANSWER

YOU NEED ONE SIGN OF THE SAME WHEN MULTIPLYING TO BE A POSITIVE AS YOUR ANSWER

YOU NEED ONE SIGN TO BE DIFFERENT FROM THE OTHER WHEN MULTIPLYING TO GET A NEGATIVE AS YOUR ANSWER

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3 years ago

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Answer:

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2 years ago

A total investment of $10,700 is made into two savings accounts. One account yields 5% simple interest and the other 6% simple i

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Answer:

He earn $535.00 in the 5% account

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5 0

2 years ago

Read 2 more answers

The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin

tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950 $e^{0.45t}$

a) rate of growth is

Bacteria growth model N(t) = no $e^{rt}$

Where r is the growth rate

hence r = 0.45

= 45%

b) Initial population of culture at t = 0

n(0) = 950 $e^{0.45(0)}$

= 950 $e^{0}$

= 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) = 950 $e^{0.45(5)}$

= 950 $e^{2.25}$

= 9013.35

= 9013 bacteria

6 0

3 years ago