Round to the nearest tenth if neccessary 69.904 divided by 34
2 answers:
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Answer:
7.07
Step-by-step explanation:
<h2><u>Length</u></h2>a square has equal length on each side
hence is the perimeter is 20 it means that :
each side is 20/4 = 5
we can make a diagonal line which create 3 right angled triangles
2 sides of the triangle are 5 , this is the base and the height
to find the length we can make use of the Pythagoras theorem
c^2 = a^2 + b^2
c is the hypotenuse ( the diagonal;)
a and b are the opposite and adjacent
hence :
c^2 = 5 ^2 + 5^2
c^2 = 50
c =
c = 7.071
to 3sf
<h3><u>diagonal length = 7.07</u></h3>
We want to find 
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
Thus,
Answer: A)