A function cannot be a function if any x is repeating. The x in A has the number 1 repeating. The x is C has 2 repeating the x in D has 1 repeating.
Therefore, our answer would be (B)
Answer and Step-by-step explanation:
The computation is shown below:
Let us assume that
Spam Email be S
And, test spam positive be T
Given that
P(S) = 0.3


Now based on the above information, the probabilities are as follows
i. P(Spam Email) is
= P(S)
= 0.3

= 1 - 0.3
= 0.7
ii. 


= 0.8906
iii. 


= 0.0221
We simply applied the above formulas so that the each part could come
Answer: it will take them 48 minutes.
Step-by-step explanation:
John can mow a lawn in 80 minutes. This means that the rate at which he moans the lawn per minute is 1/80
Rocky can mow the same lawn in 120 minutes. This means that the rate at which Rocky can mow the same lawn per minute is 1/120
If they work together, they would work simultaneously and their individual rates are additive. This means that their combined working rate would be
1/80 + 1/120 = 200/9600 = 1/48
Assuming it takes t hours for both of them to clean the room working together, the working rate per hour would be 1/t. Therefore,
1/48 = 1/t
t = 48 minutes
Answer:
In order to tell if these are congruent triangles we would need to know if angles Y and V were congruent, angles X and W are congruent or if segments XU and WU were congruent.
Step-by-step explanation:
Any of these would work because you can use two different methods to telling that these are congruent triangles.
The first method is called side-angle-side. In it you need two side lengths that are congruent with a congruent angle in the middle. Since we already know that the right angle in the middle is congruent, and we know YU and VU are congruent, we would just need to know the additional side to prove congruence.
The second method is called angle, angle side. In this we need to know that two angles in a row are congruent followed by a side. Since we know the middle angle is the same, knowing either other angles would give us this method as well.
Answer:
Option (B)
Step-by-step explanation:
Length of PR = 4
RS = 4
QS = 4
For the length of PT,
PT² = RT² + PR² [Since, PT is the diagonal of rectangle PRT]
PT² = QS² + PR² [Since, RT ≅ QS]
PT² = 4² + 7²
PT² = 16 + 49
PT² = 65
Now for the length of PQ,
PQ² = QT² + PT²
PQ² = RS² + PT² [Since, QT ≅ RS]
PQ² = 4² + 65
PQ² = 16 + 65
PQ = √81
PQ = 9
Therefore, length of diagonal PQ is 9 units.
Option (B) will be the answer.