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hichkok12 [17]
3 years ago
8

The scatter plot below shows a linear association. Which is the best linear model for the data?

Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

ye its y=5x-10

Step-by-step explanation:

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WORTH 10 POINTS! 1)susan can type 4 pages of text in 10 minutes.Assuming she types at a constant rate,write the linear equation
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What should be done first to evaluate the expression?<br><br> 3 + (5 - 3)2 × 4
Kryger [21]

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19

Step-by-step explanation:

19 is the answer I think so

5 0
2 years ago
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

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3 years ago
Write the equation y=3/4x+4 in standard form
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Answer:

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Step-by-step explanation:

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