All categories

3 years ago

What is the solution to 8-2b = -2/3(12b+6)

Mathematics

1 answer:

julia-pushkina [17]3 years ago

6 0

8-2b= -2/3(12b+6)
⇒ 8-2b= -8b -4
⇒ -2b+ 8b= -4-8
⇒ 6b= -12
⇒ b= -12/6
⇒ b= -2

Final answer: b= -2~

You might be interested in

Select the TWO systems of equations that have exactly one solution. Your answer: y = 3x + 1 y = -3x + 7 y = 3x + 1 y = x + 1 y =

mrs_skeptik [129]

Answer:

6657567657678678678657768666876

4 0

3 years ago

5/12 - 2/5 in fraction form

fgiga [73]

5/12-2/5=25/60-24/60
1/60

the answer is 1/60

3 0

3 years ago

Read 2 more answers

3x + 2y = 12 y = x - 9 solve by substitution

mezya [45]

Point form: (6,-3)
equation form: x=6, y=-3

7 0

2 years ago

Solve the equation in the complex number system.

tatiyna

To get rid of $x^{3}$ , you have to take the third root of both sides:
$\sqrt[3]{x^{3}} = \sqrt[3]{1}$
But that won't help you with understanding the problem. It is better to write $x^{3}-1$ as a product of 2 polynomials:
$x^{3}-1 = (x-1)\cdot (x^{2} +x +1)$
From this we know, that $x-1 = 0 => x = 1$ is the solution. Another solutions (complex roots) are the roots of quadratic equation.

3 0

2 years ago

Read 2 more answers

The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

Part B

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

Part C

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago