Answer:
The program to this question can be given as:
Program:
#include<iostream> //header file
using namespace std;
int main() //main method
{
int x[10],i,largest = 0,second_largest=0,n; //variable
cout << "Enter Number of elements :"; //message
cin>>n;
cout << "Insert array elements :"; //message
for(i=0;i<n;i++) //insert elements in array
{
cin >>x[i];
}
//Finding Largest element
for(i=0;i<n;i++)
{
if (x[i]>largest)
{
largest = x[i];
}
}
//finding second largset element
for(i=0;i<n;i++)
{
if (x[i]>second_largest)
{
if(x[i]==largest)
{
continue; //Ignoring largest in order to get second largest
}
second_largest=x[i];
}
}
//print value
cout <<"Largest Number:"<<largest<<endl;
cout <<"Second Largest Number:"<<second_largest;
return 0;
}
Output:
Enter Number of elements :5
Insert array elements :33
45
75
87
23
Largest Number:87
Second Largest Number:75
Explanation:
In the above program firstly we define the header file then we define the main method in the main method we define the array and other variables. We first input the number for the size of the array. Then we insert array elements after inserting array elements we search the largest number and the second largest number in the array. To search the largest number in the array we use the loop. To search the first largest number we define a condition that array is greater than the largest number and store the value into the largest variable. Then we check the second largest number in the array for this we use two conditions that are array is greater than the second largest number in this we use another condition that is array is equal to the largest number. If the inner condition is true then it will move forward and end of an inner condition. In the outer condition, the value will be stored on the second_largest variable all the conditions will be done inner the loop. At the last we print values.
Yo llamaria a esto automatizacion.
Puede reducir los costos al permitir que la empresa emplee a menos personas.
Answer:
recognition
Explanation:
<h2><u>Fill in the blanks</u></h2>
When you take a multiple-choice test, you are relying on <u>recognition</u> , a means of retrieving information out of your long-term memory storage system that helps you choose the correct answer.
Answer:
The Pointer P becomes a dangling pointer.
Explanation:
int calculate(){
int *p = (int*)malloc(10);
*p = 10;
return p;
}
In this program, the scope of p is only with the calculate function block. Hence, once the compiler comes out of the function, it can no more access the pointer p or the memory location p is pointing to. To overcome the dangling pointer, we need to declare p as static, so that the scope of p is throughout the program.
Answer:
In the memory sticks/cards of the digital camera
Explanation:
Many digital cameras come with removable storage cards in the form of memory cards, memory sticks and flask cards. Activities (pictures and videos) captured with these digital cameras are stored in these removable storage cards. These makes it easy for users to remove the storage cards and insert into other devices.
