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3 years ago

Simplify: (2x^4y^3) • (6x^3y^2)

1 answer:

8 0

12•x^7•y^5

When multiplying, you multiply the coefficients (which would be 2 and 6 in this case) then with the exponents you add the exponents and give them to the common variable
X^4•x^3
You add 4 and 3
x^7

I hope this makes sense:)

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Write three multiples of 4/5

Greeley [361]

workings...

3x4=12

answer: 12/5 or 2 2/5

4 0

3 years ago

What is the distance between the points (14, 29) and (14, 58) in the coordinate plane?

ss7ja [257]

$Distance= \sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1})^2} = \sqrt{(58-29)^{2}+(14-14)^{2}} =29

But because x_{1}=x_{2}, 

 and it is a vertical segment, 

it is enough to find abs(y_{2} -y_{1})=|58-29|=29$

6 0

3 years ago

Read 2 more answers

Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p

Alla [95]

Answer:

Part A : D.) $2w + 2(2w+ 1) = 29$

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = $2w+1$

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = $2(2w+1)+2w$

we have given the perimeter, so on substituting the value, we get;

$29=2(2w+1)+2w$

Hence The equation used to find the width is $29=2(2w+1)+2w$ .

Now we solve for 'w'.

Applying distributive property, we get;

$4w+2+2w=29\\\\6w+2=29$

Subtracting both side by '2' we get

$6w+2-2=29-2\\\\6w=27$

Dividing both side by 6 we get;

$\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft$

Width of the sandbox = 4.5 ft

Length of the sandbox = $2w+1=2\times4.5 +1 = 9+1=10\ ft$

Hence Length of the sandbox is 10 feet.

3 0

3 years ago

Consider f(x) = -(x+7)^2 +4. check all that apply

kirill [66]

-the equation is a quadratic

-the axis of symmetry is x=-7

-the graph has a relative maximum

5 0

3 years ago

Please help!

agasfer [191]

Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

6x+3y=-12

Now just subtract it from the other equation.

6x+3y=-12
5x+3y=-6

***x=-6***

Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

2(-6)+y=-4
-12+y=-4
y=8

Brainliest my answer if it helps you out?

4 0

3 years ago

Read 2 more answers