Question:
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?
Answer:
1/72
Step-by-step explanation:
<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is 1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is 1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>
<em>I had this same question on my test!</em>
<em>Hope this helped! Good Luck! ~LILZ</em>
Answer:
$30,000 and $55,000
Step-by-step explanation:
If 4.5% loan is x, and the 6% loan is y, then:
x + y = 85000
0.045x + 0.06y = 4650
Solve the system of equations with substitution or elimination. Using substitution:
0.045x + 0.06(85000 − x) = 4650
0.045x + 5100 − 0.06x = 4650
450 = 0.015x
x = 30000
y = 55000
First, isolate the decimal. second, put it over the correct denominator based on the decimal place: 96/100. Next, divide by a number that goes into both 96 and 100. 4 works.... 24/25. And that is your answer, after you add the original 2 back: 2
