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Masja [62]
3 years ago
13

Can someone help me fast thanks so much i need help on this math problem thanks again:)

Mathematics
1 answer:
azamat3 years ago
8 0
  28.0
+14.2  =  42.2 could i plz get a brainleist  i really need it
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-. For each equation below, determine whether
Andre45 [30]

Answer:

Step-by-step explanation:

The first answer a, is not a linear function because of the first term, 2√(x), this is basically 2(x^(1/2)) which means that it is not linear

B is linear because there are no exponents in any of the variables.

C is not linear because it forms a circle when graphed

D is linear because there are no exponents in any of the variables.

E is linear because there are no exponents in angy of the variables.

F is linear because there are no exponents in any of the variables.

G is not linear because it is a quadratic equation.

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3 years ago
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A tv that normally cost $800
sukhopar [10]

what is the question it might be an Sony-75"

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2 years ago
A pharmacist wants to make 36ml of a 65% hydrogen peroxide solution. how many pls of 75% hydrogen peroxide must he mix with 57%
faltersainse [42]

Answer:

16 mls of the 75% solution and 20 mls of the 0.57% solution.

Step-by-step explanation:

Set up a system of equations:

Let x = volume of 75% solution and y be volume of 57% solution

0.75x + 0.57y = 36*0.65

0.75x + 0.57y = 23.4.......(1)

x + y = 36.........(2)

From equation (2):

y = 36 - x

Substituting this into equation(1):

0.75x + (0.57(36 - x) = 23.4

0.75x + 20.52 - 0.57x = 23.4

0.18x = 23.40 - 20.52 = 2.88

x = 2.88/0.18

x = 16

so from equation (2): y = 36-16 = 20.

8 0
2 years ago
10,000,000,000×200,000
Snowcat [4.5K]
10,000,000,000×200,000 = 2e+15
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2 years ago
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A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

4 0
3 years ago
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