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Art [367]
3 years ago
14

Johnny invested $1000 in savings account that yields 2% interest annually. How much will Johnny's investment be worth in 10 year

s?
Mathematics
1 answer:
Ann [662]3 years ago
4 0
Calculate the interest in a year
Multiply the annual percentage of interest by the investment to find the interest.
interest in a year = 2% × 1,000
interest in a year = 0.02 × 1,000
interest in a year = 20
The annual interest is $20

Calculate the interest after 10 years
Multiply the annual interest by 10
interest 10 years = 20 × 10
interest 10 years = 200
The sum of interest after 10 years is $200

Find total investment
investment = first investment + interest in 10 years
investment = 1,000 + 200
investment = 1,200

The investment will be worth $1,200 in 10 years
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4 years ago
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Nimfa-mama [501]

Answer:

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3 years ago
For what values of $x$ is it true that $x^2 - 5x - 4 \le 10$? Express your answer in interval notation.
dybincka [34]

Answer:

  x ∈ [-2, 7]

Step-by-step explanation:

The given equation ...

  x^2 -5x -4 ≤ 10

can be rewritten as ...

  x^2 -5x -14 ≤ 0

and factored as ...

  (x +2)(x -7) ≤ 0

Clearly, the "or equal to" condition will be met when x=-2 and x=7. For values of x between these numbers, one factor is negative and the other is positive. Hence the product will be negative. So, numbers in that interval are the solution set.

  x ∈ [-2, 7]

5 0
3 years ago
Solve the system of linear equations using the Gauss-Jordan elimination method.
mixas84 [53]

Answer:

x = -0.6

y = 2.2

z = 2

Step-by-step explanation:

2x + y - 2z = -3

x + 3y - z = 4

3x + 4y - z = 5

Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)

2 1 -2 -3

1 3 -1 4

3 4 -1 5

R1 / 2 → R1 (divide the 1 row by 2)

1 0.5 -1 -1.5

1 3 -1 4

3 4 -1 5

R2 - 1 R1 → R2 (multiply 1 row by 1 and subtract it from 2 row); R3 - 3 R1 → R3 (multiply 1 row by 3 and subtract it from 3 row)

1 0.5 -1 -1.5

0 2.5 0 5.5

0 2.5 2 9.5

R2 / 2.5 → R2 (divide the 2 row by 2.5)

1 0.5 -1 -1.5

0 1 0 2.2

0 2.5 2 9.5

R1 - 0.5 R2 → R1 (multiply 2 row by 0.5 and subtract it from 1 row); R3 - 2.5 R2 → R3 (multiply 2 row by 2.5 and subtract it from 3 row)

1 0 -1 -2.6

0 1 0 2.2

0 0 2 4

R3 / 2 → R3 (divide the 3 row by 2)

1 0 -1 -2.6

0 1 0 2.2

0 0 1 2

R1 + 1 R3 → R1 (multiply 3 row by 1 and add it to 1 row)

1 0 0 -0.6

0 1 0 2.2

0 0 1 2

x = -0.6

y = 2.2

z = 2

7 0
3 years ago
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