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4 years ago

MATH HELP WITH TRIANGLES AND POSTULATES

Mathematics

2 answers:

makvit [3.9K]4 years ago

7 0

I believe it would be C! I hope all is well, and you end up passing this test or assignment! (:

Maurinko [17]4 years ago

4 0

C
because AB = DE
and angle BAE = angle DEA because ACE is an isosceles triangle
AE = AE Reflexive side
Hence C is correct answer

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Y=1/2x+4 <br> I need to help solving this!! :)

sweet [91]

Answer: so the 4 is the y intercept and thats where u plot one point (0,4) then 1/2x is the slope so its rise/run so it goes up 1 and goes over 2 squares. so like the second point you would plot is (2,5) then you draw the line

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3 years ago

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Express the complex number in trigonometric form. <br><br> -6 + 6 <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFor

enot [183]

Answer:

$\large\boxed{-6+6\sqrt3i=12\left(\cos\dfrac{2\pi}{3}+i\sin\dfrac{2\pi}{3}\right)}$

Step-by-step explanation:

Look at the picture.

The trigonometric form of a complex number:

$z=|z|(\cos\alpha+i\sin\alpha)$

where:

$|z|=\sqrt{a^2+b^2}\\\\\cos\alpha=\dfrac{a}{|z|}\\\\\sin\alpha=\dfrac{b}{|z|}$

We have the complex number:

$z=-6+6\sqrt3i\to a=-6,\ b=6\sqrt6$

Substitute:

$|z|=\sqrt{(-6)^2+(6\sqrt3)^2}=\sqrt{36+108}=\sqrt{144}=12$

$\cos\alpha=\dfrac{-6}{12}=-\dfrac{1}{2}\\\\\sin\alpha=\dfrac{6\sqrt3}{12}=\dfrac{\sqrt3}{2}$

Therefore

$\alpha=\dfrac{2\pi}{3}$

Finally:

$-6+6\sqrt3i=12\left(\cos\dfrac{2\pi}{3}+i\sin\dfrac{2\pi}{3}\right)$

8 0

3 years ago

You receive $1,000 to put in the bank. You place it in an account that pays 6% annual interest compounded continuously. How much

sergey [27]

$2054.43 or $2054 in 12 years

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3 years ago

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If your piece of graph paper goes only 20 blocks above the x-axis, then where will the

dlinn [17]

The function will go somewhere between x = 4 and x = 5

<h3>How to determine the location of the function?</h3>

The function is given as:

y = 2^x

The question implies that:

If the maximum y value on a graph is x = 20; What is the maximum x value on the graph of y = 2^x

To do this, we start by setting y to 20.

So, we have:

2^x = 20

Take the logarithm of both sides

x log(2) = log(20)

Divide by log(2)

x = 4.32

4.32 is between 4 and 5

Hence, the function will go somewhere between x = 4 and x = 5