Answer:
the CPU utilization decreases as the degree of multiprogramming is increased.
Explanation:
The fundamental concept is that allocating a process with too few frames causes too many and frequent page faults. This implies that the CPU does not perform any useful work and thus its utilization would decrease drastically. In this case, the long-term scheduler, in a bid to improve the utilization of the CPU, would load more processes into the memory so as to increase the extent of multiprogramming. As a result, there would be more decrease in the utilization of the CPU, leading to a chained reaction of higher page faults, which is then followed by a corresponding increase in the multiprogramming degree, usually known as thrashing.
What?? explain your question
Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
D. A spike of electricity. They are fast and have a short duration.
Answer:
ppl
Explanation:
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