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irakobra [83]
3 years ago
11

Poonam is five times as old as Shalini. The sum of their ages is 72

Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

Shalini = 12

Poonam = 60

Step-by-step explanation:

Let p = poonams age

Let s = shalini's age

p = 5s

p+s = 72

Substitute the first equation into the second equation

5s+s = 72

Combine like terms

6s= 72

Divide by 6

6s/6 = 72/6

s = 12

p = 5s =5*12 = 60

Shalini = 12

Poonam = 60

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Determine the value of each variable in the figure below. Keep answers in simplest<br> radical form.
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Answer:

  a = 21

  b = 63

  c = 42√3

  d = 21√3

Step-by-step explanation:

The sides of a 30°-60°-90° triangle have the ratios 1 : √3 : 2. The given side (42) is the longest side of the smallest triangle, and the shortest side of the largest triangle.

That means the other sides of the smallest triangle will be ...

  a = 42/2 = 21

  a+b = 2(42) = 84

  b = (a+b) -a = 84 -21 = 63

  d = 21√3 . . . . middle-length side of the smallest triangle

  c = 42√3 . . . . middle-length side of the largest triangle

The values of the variables are ...

  • a = 21
  • b = 63
  • c = 42√3
  • d = 21√3

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3.Transitive Property Of Congruence

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Select all equations that are equivalent to 5x + 6/2= 3-(4x +12)​
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Step-by-step explanation:

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Write a number that is the same when rounded to the nearest hundred and ten
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A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0
2 years ago
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