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stepladder [879]

3 years ago

14

Which of the following are composite numbers

1 answer:

mamaluj [8]3 years ago

7 0

33 is composite
49 is composite
21 is composite

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Add 4x²y,-2xy²,-5xy²,3x²y plz explain

Vinil7 [7]

4x^2 - 2xy^2
5xy^2 +
3x^2y
_____________
12x^5y^4-2xy^2

This is so because 4+5+3 is 12, then using laws of indices to add your x and y you get x^5 and y^4

To simplify your answer to the lowest you have it in the form of
3x^2y^2(4x^2y - 2xy^2)

If you multiply this as well you get the same answer I got with the addition

3 0

3 years ago

Can anyone please tell me if this is correct? If not help explain me the answer? Thank you

iris [78.8K]

There is on equation to solve for x so I think it is wrong

6 0

3 years ago

I need help. I’ve been stuck

solniwko [45]

Ok RYU? Isn’t it 110*?

3 0

2 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago

Find the values of x and y

Mkey [24]

Answer:

x = 78º

y = 35º

Step-by-step explanation:

These are isosceles triangles

two angles are congruent

-----------------------------

x + 51 + 51 = 180

x = 180 - 102

x = 78º

y + y + 110 = 180

2y = 70

y = 35º

3 0

2 years ago