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Natasha2012 [34]
3 years ago
13

WILL GIVE BRAINLIEST. PLZ HELP. 23points :D

Mathematics
2 answers:
Allisa [31]3 years ago
4 0
A)

well, the y-intercept for f(x) is at \bf f(x)=\stackrel{slope}{\cfrac{2}{3}}x+\stackrel{y-intercept}{4}

as you can see from the slope-intercept form is at 4, and it has an slope of 2/3.

for g(x), well an y-intercept is when x = 0, what is it from that table?  well, is at 0,3, so when x = 0, y = 3, so no dice on that one.



c)

whenever an x-intercept occurs, y = 0, for f(x) that's at 

\bf 0=\cfrac{2}{3}x+4\implies -4=\cfrac{2}{3}x\implies -12=2x\implies -6=x

what about the x-intercept for g(x)?  well, let's check, when is y = 0?  aha!  at -9, 0, so when y = 0, x = -9, so no dice on that one either.



d)

well, what is the slope of g(x) anyway?  well, let's pick two points off the table to get it hmmm the first two let's use,

\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -9 &,& 0~) 
%  (c,d)
&&(~ -6 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-0}{-6-(-9)}\implies \cfrac{1-0}{-6+9}\implies \cfrac{1}{3}

and from a), using the slope-intercept form, we know f(x) has a slope of 2/3.

well, 2/3 is larger than 1/3, so no dice.



b)

well, you already know.
krek1111 [17]3 years ago
4 0

Answer:

the answer is d

Step-by-step explanation:

Consider the function f(x)=2/3x+4 and the linear function g(x) represented in the table.

x g(x)

−9 0

−6 1

0 3

3 4

9 6

Which statement about the functions is true?

a.f(x) and g(x) have the same y-intercept.

b.The slope of f(x) is greater than the slope of g(x).

c.f(x) and g(x) have the same x-intercept.

d. The slope of g(x) is greater than the slope of f(x).

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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
3 years ago
1/4 (4x + 8)mi need help with this question
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4 years ago
Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will
VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

A = P\left(1 + \dfrac{r}{n}\right)^{nt}

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0
4 years ago
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