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natima [27]
2 years ago
13

Counting by thousands, write five numerals from 1578 onwards.​

Mathematics
2 answers:
Sophie [7]2 years ago
5 0

Answer:

1578 + 1000 = 2578

2578 + 1000 = 3578

3578 + 1000 = 4578

4578 + 1000 = 5578

5578 + 1000 = 6578

Fofino [41]2 years ago
3 0
2578,3578,4578,5578,5678
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A country's population in 1994 was 182 million. In 2002 it was 186 million. Estimate the population in 2004 using the exponentia
iogann1982 [59]
\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
t=0\qquad P=182
\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\

\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
t=8\qquad P=186
\end{cases}\implies 186=182e^{k8}
\\\\\\
\cfrac{186}{182}=e^{8k}\implies ln\left( \frac{93}{91} \right)=ln(e^{8k})\implies ln\left( \frac{93}{91} \right)=8k
\\\\\\
\cfrac{ln\left( \frac{93}{91} \right)}{8}=k\implies 0.0027\approx k\implies \boxed{P=182e^{0.0027t}}

what's the population in 2004?  well,  from 1994 to 2004 is 10 years later, so t = 10

plug that in, to get P for 2004
3 0
3 years ago
ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i
Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

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So the relation is:

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The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

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7 0
1 year ago
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den301095 [7]

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3 years ago
What is the domain
xenn [34]
<h3>Answer: Give the domain and the range of each quadratic function whose graph is described. The vertex is (−1,−2)(−1,−2) and the parabola opens up.</h3>

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2 years ago
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In a shipment of new cookies for a store, 4/12 of the cookies were sugar and 1/5 were oatmeal. The remainder of the cookies were
Lisa [10]

Answer:

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Step-by-step explanation:

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1 - \frac{8}{60}

\frac{60}{60} - \frac{8}{60} = \frac{52}{60} = 13/15

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