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2 years ago

Counting by thousands, write five numerals from 1578 onwards.

Mathematics

2 answers:

Sophie [7]2 years ago

5 0

Answer:

1578 + 1000 = 2578

2578 + 1000 = 3578

3578 + 1000 = 4578

4578 + 1000 = 5578

5578 + 1000 = 6578

Fofino [41]2 years ago

3 0

2578,3578,4578,5578,5678

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Given a=4, b=-2 and c=8, evaluate a-b-c

atroni [7]

Filling them in it would be ; 4 - (-2) - 8
And a negative against a negative equals a plus so ; 6 - 8 = your answer

8 0

3 years ago

2a + b = 3 and a - 3b = 5

vfiekz [6]

Answer:

a= 2 b=-1

Step-by-step explanation:

a-3b=5

or, a= 5+3b_(i)

substituting value of a in 2a+b=3,

2×(5+3b)+b=3

or, 10+6b+b=3

or, 7b=3-10

or, 7b=-7

b= -1

substituting value of b in(i),

a=5+3b

=5+3×(-1)

=5-3

6 0

3 years ago

Evaluate the given integral by changing to polar coordinates. sin(x2 + y2) dA R , where R is the region in the first quadrant be

koban [17]

Set

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dA=r\,\mathrm dr\,\mathrm d\theta$

The region $R$ is given in polar coordinates by the set

$R=\left\{(r,\theta)\mid2\le r\le3,0\le\theta\le\dfrac\pi2\right\}$

So we have

$\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_2^3r\sin(r^2)\,\mathrm dr\,\mathrm d\theta=\boxed{\frac\pi4(\cos4-\cos9)}$

8 0

3 years ago

Find the equation of the line that is parallel to the given line and passes through the given point

Sati [7]

Answer:

$\huge\boxed{y=-\dfrac{1}{4}x-1\to x+4y=-4}$

Step-by-step explanation:

$\text{Let}\ k:y=m_1x+b_1;\ l:y=m_2x+b_2\\\\l\ ||\ k\iff m_1=m_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\==========================\\\\\text{We have}\ x+4y=-6.\\\text{Convert to the slope-intercept form:}\\\\x+4y=-6\qquad\text{subtract}\ x\ \text{from both sides}\\\\4y=-x-6\qquad\text{divide both sides by 4}\\\\y=\dfrac{-x}{4}-\dfrac{6}{4}\\\\y=-\dfrac{1}{4}x-\dfrac{3}{2}\to m_1=-\dfrac{1}{4}$

$\text{Lines are to be parallel. Therefore}\ m_2=-\dfrac{1}{4}.\\\\\text{We initially have the form equation}\ y=-\dfrac{1}{4}x+b.\\\\\text{The line passes through the point}\ (9,\ -3).\\\\\text{Substitute the coordinates of the point to the equation of a line:}\\\\x=9,\ y=-3\\\\-3=-\dfrac{1}{4}(9)+b\\\\-3=-\dfrac{9}{4}+b\qquad\text{add}\ \dfrac{9}{4}\ \text{to both sides}\\\\-\dfrac{12}{4}+\dfrac{9}{4}=b\to b=-\dfrac{3}{4}$

$x=8,\ y=-3\\\\-3=-\dfrac{1}{4}(8)+b\\\\-3=-2+b\qquad\text{add 2 to both sides}\\\\-1=b\to b=-1$

$\text{Therefore the equation is:}\ y=-\dfrac{1}{4}x-1.\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y=-\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4y=-x-4\qquad\text{add}\ x\ \text{to both sides}\\\\x+4y=-4$

5 0

3 years ago

If |lm and m<6 = 4x - 15 and m<7 = x+30, then m<6 =<br> 35<br> 45<br> 39<br> 15

pentagon [3]

Answer:

∠ 6 = 45°

Step-by-step explanation:

∠ 6 and ∠ 7 are alternate angles and are congruent, thus

4x - 15 = x + 30 ( subtract x from both sides )

3x - 15 = 30 ( add 15 to both sides )

3x = 45 ( divide both sides by 3 )

x = 15

Thus

∠ 6 = 4x - 15 = 4(15) - 15 = 60 - 15 = 45°

4 0

3 years ago

Counting by thousands, write five numerals from 1578 onwards.​

Counting by thousands, write five numerals from 1578 onwards.