Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Answer:
6(a)+14
Step-by-step explanation:
First you need to find f(a) and f(2) separately, then add them together after
f(a) = 6(a)+1
f(2) = 6(2)+1 = 12+1 = 13
so f(a)+f(2) = 6(a)+1+13 = 6(a)+14
Hope this helps you If you need any more help let me know in the comments
Answer:
251.4cm² is the area of the cone-shaped vase.
The answer to this question is letter B