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Paladinen [302]
3 years ago
13

The difference of 17 and 5 tines a number

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

You can answer this problem in two different ways: the first being (17 - 5) * x, and the second being 12 * x.

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The answer is B: (x-1)(x-6)(x+6)
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2 years ago
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A bakery owner asked 150 customers to taste a new type of cookie and found that 60 people liked it's taste.
FrozenT [24]

Answer:

yes

Step-by-step explanation:

Here is the complete question :

A bakery owner asked 150 customers to taste a new type of cookie and found that 60 people liked its taste. 40% of the surveyed customers like the taste of the cookie. Is it an example of descriptive statistics?

Descriptive statistics are used to summarise the features or characteristics of a data or sample. It provides information on the features of sample collected.

Types of  descriptive statistics

1. Measures of central tendency :

They include mean, median and mode

Mode refers to a value that appears most frequently in a data set.

Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order

Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of the numbers / total number

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5 0
2 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
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GarryVolchara [31]

Answer:

Complementary

Step-by-step explanation:

3 0
3 years ago
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Y=-4x+3-x because if it's -y=4-3+x y is not alone so you need to make y positive and switch the rest of the operations so it can be y=-4+3-x
6 0
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