THIS IS THE COMPLETE QUESTION BELOW;
The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.
Answer
Margin error =210.8
Given:
standard deviation of 425
sample mean x=1520 dollars.
random sample n= 22
From the question We need to to calculate the margin of error for the confidence interval for the population mean .
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Change 13% as a fraction. It will be 13/100
Now, which is bigger? 13/100 or 3/25
Cross multiply and 13/100 is bigger.
13 3
___ X ____
100 25
13×25=325 and 3×100=300. Now you know 13/100 is bigger.
The answer is 13/100
Answer:
B
Step-by-step explanation:
Cos is the adjacent side over the hypotenuse. The adjacent side to <E is side ED. The hypotenuse is side EF. ED/EF. They do not go right out and give you this choice, but you see that B says the same thing.
<h3>
Answer: 20% discount</h3>
Work Shown:
amount saved = 84-67.20 = 16.80 dollars
Divide this over the original larger price to get 16.80/84 = 0.20 = 20%
Note how 20% of 84 = 0.20*84 = 16.80 to help check the answer.
Or we can say 0.80*84 = 67.20 which also helps confirm the answer.
The 0.80 is from the fact that you save 20% but still have to pay the remaining 80%
16*x=4 also if u dont understand *=division
