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mr Goodwill [35]
3 years ago
8

Factor out -1/4 out of -1/2x-5/4y

Mathematics
1 answer:
pentagon [3]3 years ago
8 0
Greetings!

\frac{1}{2}x- \frac{5}{4}y
Factor -1/4. How? To factor a polynomial, you divide all the terms by the GCF (The Greatest Common Multiple.)  
=-1/4(\frac{1}{2}x/(-1/4)- \frac{5}{4}y/(-1/4))
Simplify.
=-1/4(\frac{1}{2}x*(-4/1)- \frac{5}{4}y*(-4/1))
=-1/4(\frac{-4}{2}x- \frac{-20}{4}y)
Reduce Fractions to simplest form.
=-1/4(-2x-(-5y))
The Factor Polynomial Is:
=-1/4(-2x+5y)

Hope this helps.
-Benjamin
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3 years ago
Find the standard deviation of
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Answer:

11.5

The sample standard deviation measures the spread of a data distribution of the sample. It is usually used to estimate the population standard deviation

7 0
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Write the equation in slope-intercept form of a line that has a slope of 1/3 and passes through the point (-6, 0).
Vesna [10]

Answer: y = 1/3x +2

Step-by-step explanation:

The equation of line in slope - point form is given as:

y - y_{1} = m ( x - x_{1} )

m = 1/3

y_{1} = 0

x_{1} = -6

substituting into the formula , we have

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y = 1/3x +2

5 0
3 years ago
Read 2 more answers
The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer se
tankabanditka [31]

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

<u><em>Difference Scores Calculations</em></u>

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

<u><em>T-value Calculation</em></u>

<u><em>Pooled Variance= Sp²</em></u>

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

7 0
2 years ago
The student council wants to rent a chocolate fountain for an overnight dance-a-thon. Their budget allows them to spend a maximu
vekshin1
$125 is a "must budget" so it will be the constant in the inequality

The fountain is $30 per hour. If they spend x hours, then their budget for fountain will be
fountain = 30x

The inequality
Their budget is maximum $250, that means they are able to spend less than or equal to $250
constant + fountain ≤ 250
125 + 30x ≤ 250
<em>This is the inequality expression</em>
6 0
3 years ago
Read 2 more answers
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