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Dmitry [639]
1 year ago
9

If a gallon of paint covers 400 square feet, how many gallons are needed to paint a retaining wall that is 269 feet long and 4 f

eet high ? Round the answer up to the nearest whole gallon

Mathematics
1 answer:
Nuetrik [128]1 year ago
5 0

The area of a rectangular shape is given by

A=l\times b

Given:

It is given that a gallon of paint covers 400 square feet, and wall is 269 feet long and 4 feet high .

Now the area of wall will be

A=269\times4

Since,

\begin{gathered} 400\text{ sq f}eet=\text{ 1gallon} \\ 1\text{ sq f}eet=\frac{1}{400}gallon \\ 269\times4\text{ sq f}eet=\frac{1}{400}\times269\times4 \\ =\frac{269}{100} \\ =2.69\text{ gallon} \\ =3\text{ galllon} \end{gathered}

So, the ewall requires approx 3 gallon of paint.

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In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
A piano teacher has 4 1/2 hours available to teach in a night. Each lesson will last 1 1/2 hours. How many lessons can the teach
kherson [118]

Answer:

3 classes

Step-by-step explanation:

The teacher can schedule 3 classes in a night because 4 1/2 divided by 1 1/2 is 3.

hope this helps!!

8 0
3 years ago
Read 2 more answers
Plz help me, thank you
Kruka [31]

Answer:

P=40(1.03526)^{t}

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^{t}

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

The initial number of bacteria is Po=40 and it doubles (P=2Po) at t=20 min. With that point we can find the value of r:

2P_o=P_o(1+r)^{20}

Simplifying:

(1+r)^{20}=2

Solving for 1+r:

1+r=\sqrt[20]{2}

1+r=1.03526

The exponential function that models the situation is:

\mathbf{P=40(1.03526)^{t}}

4 0
2 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
2 years ago
The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of 0.5 min
Hitman42 [59]
Given:
μ = 2 min, population mean
σ = 0.5 min, population standard deviation

We want to find P(x>3).

Calculate the z-score
 z= (x-μ)/σ = (3-2)/0.5 = 2

From standard tables, obtain
P(x ≤ 3) = P(z ≤ 2) = 0.9772
Therefore
P(x > 3) = P(z > 2) = 1 - 0.9772 = 0.0228

Answer: 0.02275
8 0
3 years ago
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