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ahrayia [7]
4 years ago
5

How do you solve for x in m=2(x n)?

Mathematics
1 answer:
Klio2033 [76]4 years ago
4 0
M = 2(x + n)
m/2 = x + n
x = m/2 - n
You might be interested in
What is the number to the right of the decimal point called?
koban [17]
Tenths. Hope this helped.
5 0
3 years ago
Hey, Y'all. Was wonderin' bout this pesky question that got me a bit stumped. Thank ya for your help.
puteri [66]
Answer: Choice B) (24,10)

---------------------------------------------------------

Work Shown:

2x - 4y = 8
2( x ) - 4y = 8
2( 3y-6 ) - 4y = 8 ... notice x has been replaced with 3y-6
2(3y)+2(-6) - 4y = 8
6y-12 - 4y = 8
2y-12 = 8
2y-12+12 = 8+12 ... add 12 to both sides
2y = 20
2y/2 = 20/2 ... divide both sides by 2
y = 10

If y = 10, then
x = 3y-6
x = 3*10-6 ... replace y with 10
x = 30-6
x = 24

Put together, the solution is (x,y) = (24,10)
which is why the answer is choice B

As a check, we can plug (x,y) = (24,10) into each equation
x = 3y-6
24 = 3*10 - 6
24 = 30 - 6
24 = 24 ... true equation
and similarly for the second equation as well
2x-4y = 8
2*24 - 4*10 = 8
48 - 40 = 8
8 = 8 ... true equation
Both equations are true when (x,y) = (24,10) so the solution is confirmed
4 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
Three times the difference between 4 times h and five is 45
Anestetic [448]

3(4h-5) =45

12h-15=45

+15 +15

12h = 60

÷12 ÷12

h = 5

5 0
3 years ago
4000 Is blank times as 4
Ket [755]
4000/4
is equal to your answer
which is 1000.
7 0
3 years ago
Read 2 more answers
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