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pychu [463]
3 years ago
8

The figure ABCD is made up of two different triangles.ABD is a right-angled triangle.AB=25 cm,AD=60 cm,BD=65 cm and CE=45 cm.Fin

d the area of figure ABCD.​

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

the area of ABCD is 135

Virty [35]3 years ago
5 0

Answer:

2212.5 cm²

Step-by-step explanation:

ABCD is constructed from 2 right triangles ABD and BCD

The area (A ) of a triangle is calculated using the formula

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

In ΔABD, b = AD = 60 and h = AB = 25, hence

A = \frac{1}{2} × 60 × 25 = 30 × 25 = 750 cm²

-----------------------------------------------------------------------------

In ΔBCD, b = BD = 65 and h = CE = 45, hence

A = \frac{1}{2} × 65 × 45 = 1462.5 cm²

----------------------------------------------------------------------------

The area of figure ABCD = area of ΔABD + area of ΔBCD

A = 750 + 1462.5 = 2212.5 cm²

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Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t​, find
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Step-by-step explanation:

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v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5

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v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}

a(44)=10\: \frac{ft}{s^2}

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