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Firlakuza [10]
3 years ago
12

Doris made 80 cookies this week. She baked 4 less than three times the total she made last week. Which equation, when solved for

x, gives the number of cookies she baked last week?
Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

The equation is  3x-4=80

The value of x is 28 cookies

Step-by-step explanation:

Let

x ---->  the number of cookies she baked last week

we know that

The number of cookies she baked last week multiplied by 3 minus 4 must be equal to 80 cookies

so

The linear equation that represent this situation is

3x-4=80

solve for x

3x=80+4\\3x=84\\x=28\ cookies

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Betsy is shopping for a new rug, and she finds a square rug that she wants to purchase for her living room. Before purchasing th
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Options:

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6 0
3 years ago
Read 2 more answers
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

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